'In Java, how does BitSet get range works?

pls help me with below code snippet understanding
/*package whatever //do not write package name here */

import java.io.*;
import java.util.BitSet;

class GFG {
    public static void main (String[] args) {
        BitSet bs=new BitSet();
        bs.set(4);
        bs.set(0);
        bs.set(3);
        bs.set(6);
        bs.set(8);
        bs.set(10);
        bs.set(11);
        bs.set(12);
        bs.set(14);
        BitSet bs2 = bs.get(4,13);
        System.out.println(bs+"  "+bs2+" "+bs2.get(2)+" "+bs2.get(4)+" "+bs2.get(5)+" "+bs2.get(12)+" "+
        bs2.get(14)+" "+bs2.get(15));
    }
}

In above code, how does bs2 gets created from using the get(4,13) on bs?

java


Solution 1:[1]

As the API documentation states bs2 is a copy of the specified range of bs starting with bit 4 and ending with bit 12 (end index is exclusive). In other words a new BitSet is created that is initialized with the bits set in that range in the original one.

Solution 2:[2]

t is true, f is false!!!

bs:

{0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14}

tffttftftftttft

100110101011101

bs(4-13)

xxxx1010101110x

cause BitSet bs2 = bs.get(4,13);

so bs2 not need 'x' !!!

so bs2 is :

tftftftttf

1010101110

0, 2, 4, 6, 7, 8 is 1

Sources

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Source: Stack Overflow

Solution Source
Solution 1 ewramner
Solution 2

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