'ImportError: cannot import name 'UserAgentMixin'
I've got an issue when I want to init my Flask DB, here is Terminal result :
user@Pc:~/Documents/test$ flask db init
Traceback (most recent call last):
File "/home/user/.local/bin/flask", line 7, in <module>
from flask.cli import main
File "/home/user/.local/lib/python3.6/site-packages/flask/__init__.py", line 17, in <module>
from werkzeug.exceptions import abort
File "/home/user/.local/lib/python3.6/site-packages/werkzeug/__init__.py", line 151, in <module>
__import__('werkzeug.exceptions')
File "/home/user/.local/lib/python3.6/site-packages/werkzeug/exceptions.py", line 71, in <module>
from werkzeug.wrappers import Response
File "/home/user/.local/lib/python3.6/site-packages/werkzeug/wrappers/__init__.py", line 30, in <module>
from .request import PlainRequest
File "/home/user/.local/lib/python3.6/site-packages/werkzeug/wrappers/request.py", line 6, in <module>
from .user_agent import UserAgentMixin
File "/home/user/.local/lib/python3.6/site-packages/werkzeug/wrappers/user_agent.py", line 1, in <module>
from ..useragents import UserAgent
File "/home/user/.local/lib/python3.6/site-packages/werkzeug/useragents.py", line 212, in <module>
from werkzeug.wrappers import UserAgentMixin # noqa
ImportError: cannot import name 'UserAgentMixin'
I'm working on an Ubuntu 18.04 LTS, using Flask, SQLAlchemy, Python and PostgreSQL. From where does this error occurs, and how can I solve it?
P.S : I followed the mega tutorial about Flask
EDIT 1 : Werkzeug is already installed
(venv) user@Pc:~/Documents/test$ pip install Werkzeug
Requirement already satisfied: Werkzeug in ./venv/lib/python3.6/site-packages
EDIT 2 : I don't know why I got this issue, but this error disappear after I removed spaces indentations
Solution 1:[1]
in my case, I found a file and a folder, both named "wrappers" in the package path, so I reinstall the package:
pip uninstall Werkzeug
pip install Werkzeug
though a little late, it may still help
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Sun Lemuria |
