'if-else statement inside jsx: ReactJS
I need to change render function and run some sub render function when a specific state given,
For example:
render() {
return (
<View style={styles.container}>
if (this.state == 'news'){
return (
<Text>data</Text>
)
}
</View>
)
}
How can I implement that without changing scenes, I will use tabs to change content dynamically.
Solution 1:[1]
As per DOC:
if-else statements don't work inside JSX. This is because JSX is just syntactic sugar for function calls and object construction.
Basic Rule:
JSX is fundamentally syntactic sugar. After compilation, JSX expressions become regular JavaScript function calls and evaluate to JavaScript objects. We can embed any JavaScript expression in JSX by wrapping it in curly braces.
But only expressions not statements, means directly we can not put any statement (if-else/switch/for) inside JSX.
If you want to render the element conditionally then use ternary operator, like this:
render() {
return (
<View style={styles.container}>
{this.state.value == 'news'? <Text>data</Text>: null }
</View>
)
}
Another option is, call a function from jsx and put all the if-else logic inside that, like this:
renderElement(){
if(this.state.value == 'news')
return <Text>data</Text>;
return null;
}
render() {
return (
<View style={styles.container}>
{ this.renderElement() }
</View>
)
}
Solution 2:[2]
You can achieve what you are saying by using Immediately Invoked Function Expression (IIFE)
render() {
return (
<View style={styles.container}>
{(() => {
if (this.state == 'news'){
return (
<Text>data</Text>
)
}
return null;
})()}
</View>
)
}
Here is the working example:
But, In your case, you can stick with the ternary operator
Solution 3:[3]
I find this way is the nicest:
{this.state.yourVariable === 'news' && <Text>{data}<Text/>}
Solution 4:[4]
I do like this and its working fine.
constructor() {
super();
this.state ={
status:true
}
}
render() {
return(
{ this.state.status === true ?
<TouchableHighlight onPress={()=>this.hideView()}>
<View style={styles.optionView}>
<Text>Ok Fine :)</Text>
</View>
</TouchableHighlight>
:
<Text>Ok Fine.</Text>
}
);
}
hideView(){
this.setState({
home:!this.state.status
});
}
Solution 5:[5]
You can do this. Just don't forget to put "return" before your JSX component.
Example:
render() {
if(this.state.page === 'news') {
return <Text>This is news page</Text>;
} else {
return <Text>This is another page</Text>;
}
}
Example to fetch data from internet:
import React, { Component } from 'react';
import {
View,
Text
} from 'react-native';
export default class Test extends Component {
constructor(props) {
super(props);
this.state = {
bodyText: ''
}
}
fetchData() {
fetch('https://example.com').then((resp) => {
this.setState({
bodyText: resp._bodyText
});
});
}
componentDidMount() {
this.fetchData();
}
render() {
return <View style={{ flex: 1 }}>
<Text>{this.state.bodyText}</Text>
</View>
}
}
Solution 6:[6]
There's a Babel plugin that allows you to write conditional statements inside JSX without needing to escape them with JavaScript or write a wrapper class. It's called JSX Control Statements:
<View style={styles.container}>
<If condition={ this.state == 'news' }>
<Text>data</Text>
</If>
</View>
It takes a bit of setting up depending on your Babel configuration, but you don't have to import anything and it has all the advantages of conditional rendering without leaving JSX which leaves your code looking very clean.
Solution 7:[7]
What about switch case instead of if-else
render() {
switch (this.state.route) {
case 'loginRoute':
return (
<Login changeRoute={this.changeRoute}
changeName={this.changeName}
changeRole={this.changeRole} />
);
case 'adminRoute':
return (
<DashboardAdmin
role={this.state.role}
name={this.state.name}
changeRoute={this.changeRoute}
/>
);
default:
return <></>;
}
Solution 8:[8]
render() {
return (
<View style={styles.container}>
(() => {
if (this.state == 'news') {
return <Text>data</Text>
}
else
return <Text></Text>
})()
</View>
)
}
Solution 9:[9]
Simple example of nested loop with if condition in React:
Data example:
menus: [
{id:1, name:"parent1", pid: 0},
{id:2, name:"parent2", pid: 0},
{id:3, name:"parent3", pid: 0},
{id:4, name:"parent4", pid: 0},
{id:5, name:"parent5", pid: 0},
{id:6, name:"child of parent 1", pid: 1},
{id:7, name:"child of parent 2", pid: 2},
{id:8, name:"child of parent 2", pid: 2},
{id:9, name:"child of parent 1", pid: 1},
{id:10, name:"Grand child of parent 2", pid: 7},
{id:11, name:"Grand child of parent 2", pid: 7},
{id:12, name:"Grand child of parent 2", pid: 8},
{id:13, name:"Grand child of parent 2", pid: 8},
{id:14, name:"Grand child of parent 2", pid: 8},
{id:15, name:"Grand Child of Parent 1 ", pid: 9},
{id:15, name:"Child of Parent 4 ", pid: 4},
]
Nested Loop and Condition:
render() {
let subMenu='';
let ssubmenu='';
const newMenu = this.state.menus.map((menu)=>{
if (menu.pid === 0){
return (
<ul key={menu.id}>
<li>
{menu.name}
<ul>
{subMenu = this.state.menus.map((smenu) => {
if (menu.id === smenu.pid)
{
return (
<li>
{smenu.name}
<ul>
{ssubmenu = this.state.menus.map((ssmenu)=>{
if(smenu.id === ssmenu.pid)
{
return(
<li>
{ssmenu.name}
</li>
)
}
})
}
</ul>
</li>
)
}
})}
</ul>
</li>
</ul>
)
}
})
return (
<div>
{newMenu}
</div>
);
}
}
Solution 10:[10]
There is no need for the if else condition in JSX. It provides a function like ternary operator to make the thing happen for you, example:
state={loading:false}
<View>
{loading ? <Text>This is a test For if else condition</Text> : <ActivityIndicator/>
</View>
Solution 11:[11]
<Card style={
{ backgroundColor: '#ffffff',
height: 150, width: 250, paddingTop: 10 }}>
<Text style={styles.title}>
{item.lastName}, {item.firstName} ({item.title})
</Text>
<Text > Email: {item.email}</Text>
{item.lastLoginTime != null ?
<Text > Last Login: {item.lastLoginTime}</Text>
: <Text > Last Login: None</Text>
}
{
item.lastLoginTime != null ? <Text >
Status: Active</Text> : <Text > Status: Inactive</Text>
}
</Card>
Solution 12:[12]
You can't provide if-else condition in the return block, make use of ternary block, also this.state will be an object, you shouldn't be comparing it with a value, see which state value you want to check, also return returns only one element, make sure to wrap them in a View
render() {
return (
<View style={styles.container}>
{this.state.page === 'news'? <Text>data</Text>: null}
</View>
)
}
Solution 13:[13]
In two ways we can solve this problem:
- Write a else condition by adding just empty
<div>element. - or else return null.
render() {
return (
<View style={styles.container}>
if (this.state == 'news'){
return (
<Text>data</Text>
);
}
else {
<div> </div>
}
</View>
)
}
Solution 14:[14]
Just Tried that:
return(
<>
{
main-condition-1 &&
main-condition-2 &&
(sub-condition ? (<p>Hi</p>) : (<p>Hello</p>))
}
</>
)
Let me know what you guys think!!!
Solution 15:[15]
For this we can use ternary operator or if there is only one condition then "&&" operator .Like this:-
//This is for if else
render() {
return (
<View style={styles.container}>
{this.state == 'news') ?
<Text>data</Text>
: null}
</View>
)
}
//This is only for if or only for one condition
render() {
return (
<View style={styles.container}>
{this.state == 'news') &&
<Text>data</Text>
}
</View>
)
}
Sources
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Source: Stack Overflow