if url intercepted then go to next part of script

Question

If URL is intercepted on Page2, selector won't be found on Page2, so I need to do nothing and page.goBack. I don't know how to skip the part of code for the page2 and go to the next part of code for the Page3. I tried several things but with no success (I'm really new on JS and Puppeteer, so I have pain to understand some basics I guess)

await page.setRequestInterception(true);
page.on('request', (request) => {
    const url = request.url();
    const filters = [
'https://example.com',
'https://example2.com',
];
    
const shouldAbort = filters.some((urlPart) => url.includes(urlPart));
   if (shouldAbort)   request.abort(),  page.goBack();
    
    else  request.continue(); 
    

});

  
  // Page 1
  await page.waitForSelector('selector')
  await navigationPromise
  await page.evaluate(()=>document.querySelector('selector').click())
  await navigationPromise  
  await page.goBack();

  // Page 2
  await page.waitForSelector('selector')
  await navigationPromise
  await page.evaluate(()=>document.querySelector('selector').click())
  await navigationPromise  
  await page.goBack();

  // Page 3
  await page.waitForSelector('selector')
  await navigationPromise
  await page.evaluate(()=>document.querySelector('selector').click())
  await navigationPromise  
  await page.goBack();