I need to get all distinct columns from the same table by the same code utilizing Hibernate

Question

I have a table with n x n relationship. That means i have a code that is repeated with only a "brand" column being different between them. The code is not the ID.

I need to have one distinct class that contains all repeatable values and with a list that has all the unique brand column values.I cannot show most of the code samples because of my company security policies. But the entity below is a mock of what i'm seeking.

`
@Entity
    @Table(name = "Table")
    public class Teste {
        @Column(name = "CODE", insertable = false, updatable = false)
        private String code;
        @Column(name = "NAME")
        private String name;
        @Column(name = "BRAND")
        private String brand;
        @OneToMany(cascade = CascadeType.ALL)
        @JoinTable(name = "BRAND", joinColumns = { @JoinColumn(name = "CODE"), @JoinColumn(name = "BRAND")})
        private Set<Model> brands = new HashSet<>();
        @Column(name = "UPDATE_DATE")
        private Date update_date;
        @Column(name = "EDITOR")
        private String editor;
        @Id
        @Column(name = "ID")
        private int id;
    }

`