I make a function, return True if all value of list is equal, otherwise False [closed]

Question

My Task is to create a function that returns True if all values in the list are the same.

Example IN/OUT:

l = [1,1,1,1,1]  # True
l = [2,2,2,2,2,5] # False

But this function not check all values.

def all_equal(list_):
    equal = list_[0]
    for a in list_:
        if a == equal:
            return True
        else:
            return False
            break
            
print(all_equal([1, 2, 1, 1]))

Answer 1

I understood you want to check if all values within a list are equal.
You get True because you use return so the loop stops after the first iteration.

def all_equal(list_):
    equal = list_[0]
    for a in list_:
        if a != equal:
            return False
    return True

(EDIT: the first approach with a variable has been removed, it's still in the post history)

Answer 2

You could use a set to remove duplicate elements from the list.

>>> l = [1, 2, 3, 4, 5, 1, 2, 3, 4, 5]
>>> set(l)
{1, 2, 3, 4, 5}

>>> l = [2, 2, 2, 2, 2, 2, 2]
>>> set(l)
{2}

If a list contains only one kind of element, then the set will contain only one element. This means that you can write the function like this:

def all_equal(list_):
    return len(set(l)) == 1

Or simply:

all_equal = lambda l: len(set(l)) == 1