How would I get the results from this to end at a value of 2?

Question

This is a countdown calculator that shows all even numbers from user input to 2. If the user inputs an odd number, it adds 1 to make the number even. I need it to stop at 2, but I'm not sure how.

startVal = int(input("Enter a starting value:"))
loss = 2
if startVal % 2 == 1:
    startVal = startVal + 1
    for i in range(2, startVal + 1):
        startVal -= loss
        print(startVal)

Answer 1

Pythons range has a third arguement which defines step size

range(start: int, end: int, step: int) -> Iterable[int]

And with that you can make decrementing loops

With knowing that you will have the next

start_val = int(input("Enter a starting value:"))
# this can be made much simpler
# if start_val % 2 == 1:
#    start_val = start_val + 1
start_val += start_val % 2
for i in range(start_val, 1, -2):
    print(i)

Also, you can mention that startVal was renamed to start_val. Avoid using CamelCase in variable namings, as Python's PEP-8 defines naming conventions. Use snake_case for variables and functions and CamelCase for class names.

Answer 2

range(start, end step)

for i in range(startVal,2,-2): startVal-=loss print(startVal)