How to stop the loop when "Q" or "q" is entered [duplicate]

Question

The code seems to continue running even after inputting Q or q. I know we need to break it from the loop but when I keep it inside the main function the output seems to be both "Thank you for using the program!" "Invalid Input, Please Enter 1-2-Q for the desired action to be performed" when I enter Q

def main():
    count = True
    while count == True:
        print("1 - Chemical formula for the Ionic Compound")
        print("2 - Chemical Name for the Ionic Compound")
        print("Q - EXIT")
        print("-----------------------------------------------")
        action = input("What action would you like to execute? ")
        menu(action)

def menu(action):
    if action == "1":
        print()
        e1 = input("Enter chemical symbol for first element: ")
        c1 = int(input("Enter the first element charge: "))
        e2 = input("Enter chemical symbol for second element: ")
        c2 = int(input("Enter the second element charge: "))
        print()
        print(chemistry.ionicCompound(e1, c1, e2, c2))
    elif action == "2":
        print()
        e1 = input("Enter chemical symbol for first element: ")
        e2 = input("Enter chemical symbol for second element: ")
        print(chemistry.ionicName(e1, e2))
    elif action == "Q" or action == "q":
        print()
        print("Thank you for using the program!")
    else:
        print()
        print("Invalid Input, Please Enter 1-2-Q for the desired action to be performed")
        print()
    print("----------------------------------------------------------------------------------")
main()

Answer 1

Try this:

RUNNING = True

def main():
    count = True
    while count == True and RUNNING:
        print("1 - Chemical formula for the Ionic Compound")
        print("2 - Chemical Name for the Ionic Compound")
        print("Q - EXIT")
        print("-----------------------------------------------")
        action = input("What action would you like to execute? ")
        menu(action)

def menu(action):
    global RUNNING
    if action == "1":
        print()
        e1 = input("Enter chemical symbol for first element: ")
        c1 = int(input("Enter the first element charge: "))
        e2 = input("Enter chemical symbol for second element: ")
        c2 = int(input("Enter the second element charge: "))
        print()
        print(chemistry.ionicCompound(e1, c1, e2, c2))
    elif action == "2":
        print()
        e1 = input("Enter chemical symbol for first element: ")
        e2 = input("Enter chemical symbol for second element: ")
        print(chemistry.ionicName(e1, e2))
    elif action == "Q" or action == "q":
        print()
        print("Thank you for using the program!")
        RUNNING = False
    else:
        print()
        print("Invalid Input, Please Enter 1-2-Q for the desired action to be performed")
        print()
    print("----------------------------------------------------------------------------------")
main()

Answer 2

The problem occurs when Django tries to serialize your Model for the purpose of creating the migration file.

If you look inside django/db/migrations/serializer.py you'll see the following:

    if '<' not in self.value.__qualname__:  # Qualname can include <locals>
        return '%s.%s' % (module_name, self.value.__qualname__), {'import %s' % self.value.__module__}
    
    raise ValueError(
        'Could not find function %s in %s.\n' % (self.value.__name__, module_name)
    )

Meaning that local functions cannot be used.