How to split a string into multiple lines in python?

Question

I am a newbie in Python. I am trying to write a program that prints the following three words (without punctuation) on three separate lines: first, second, third

m = 'first, second, third'
no_punct = ''
for x in m :
    if x != ',':
        no_punct+= x
k = no_punct.strip()
print(k)

This is the output I had from the above program:

first second third

Answer 1

You can print new lines by using '\n'. So you need to replace "," with '\n'.

m.replace(',', '\n') 
print(m)

Answer 2

You can use split to remove space, and put each element in a list, then iterate over the list and use strip to remove the occasional ',' char:

m = 'first, second, third'
for x in m.split():
    print(x.strip(','))

first
second
third

Demo:

>>> m = 'first, second, third'
>>> y = m.split()
>>> y
['first,', 'second,', 'third']
>>> y[0].strip(',')
'first'

Split docs (str.split())

Strip docs (str.strip())

Answer 3

If the pattern between words is consistently a comma followed by a space, then you can split by a comma and a space like the following:

>>> m = 'first, second, third'
>>> m.split(', ')
['first', 'second', 'third']
>>> 

Then once it's split, you can take the elements and join them with a newline, and print the result:

>>> print('\n'.join(m.split(', ')))
first
second
third

Answer 4

Instead of storing it in one variable, you can print it immediately.

for x in m :
    if x != ',':
        no_punct+= x
    else:
        print(no_punct.strip())
        no_punct = ""

A one-liner can be

print(*[x.strip() for x in m.split(',')], sep='\n')

Answer 5

A simple solution would be like this:

m = 'first, second, third'
print (m.replace(', ', '\n'))

make sure to include the space after the comma in the replace or you will end up with indents.