'how to solve: The group_list function accepts a group name and a list of members

def group_list(group, users):
  members = ___
  return ___

print(group_list("Marketing", ["Mike", "Karen", "Jake", "Tasha"])) # Should be "Marketing: Mike, Karen, Jake, Tasha"
print(group_list("Engineering", ["Kim", "Jay", "Tom"])) # Should be "Engineering: Kim, Jay, Tom"
print(group_list("Users", "")) # Should be "Users:"

python

Solution 1:^[1]

def group_list(group, users):
  members = ', '.join(users)
  return group + ': ' + members

Solution 2:^[2]

The string.join() method works well here. Get the members out of the input and into a list, and define a separator:

members = [x for x in users]
separator = ", " # Since we want commas in our string at the end

From here, get the members out of the list and into a string:

memstring = separator.join(members)

From here, you can use string formatting to get the output how you want it.

Solution 3:^[3]

def group_list(group, users):
  members = ', '.join(users)
  return group + ': ' + members

print(group_list("Marketing", ["Mike", "Karen", "Jake", "Tasha"])) # Should be "Marketing: Mike, Karen, Jake, Tasha"
print(group_list("Engineering", ["Kim", "Jay", "Tom"])) # Should be "Engineering: Kim, Jay, Tom"
print(group_list("Users", "")) # Should be "Users:"

Solution 4:^[4]

def group_list(group, users):
  members = ", ".join(users)
  return "{}: {}".format(group, members)

print(group_list("Marketing", ["Mike", "Karen", "Jake", "Tasha"])) # Should be "Marketing: Mike, Karen, Jake, Tasha"
print(group_list("Engineering", ["Kim", "Jay", "Tom"])) # Should be "Engineering: Kim, Jay, Tom"
print(group_list("Users", "")) # Should be "Users:"

Solution 5:^[5]

def group_list(group, users):

    L = users

    return ("{}: ".format(group) + " ".join(L))


print(group_list("Marketing", ["Mike", "Karen", "Jake", "Tasha"]))

print(group_list("Engineering", ["Kim", "Jay", "Tom"]))

print(group_list("Users", ""))

Solution 6:^[6]

def group_list(group, users):
members = "{}:{}".format(group, " ".join(users) )
return members

print(group_list("Marketing", ["Mike", "Karen", "Jake", "Tasha"])) # Should be 
"Marketing: Mike, Karen, Jake, Tasha"
print(group_list("Engineering", ["Kim", "Jay", "Tom"])) # Should be 
"Engineering: Kim, Jay, Tom"
print(group_list("Users", "")) # Should be "Users:"

Solution 7:^[7]

def group_list(group, users):
  return f"{group}: {', '.join(users)}"

print(group_list("Marketing", ["Mike", "Karen", "Jake", "Tasha"])) # Should be "Marketing: Mike, Karen, Jake, Tasha"
print(group_list("Engineering", ["Kim", "Jay", "Tom"])) # Should be "Engineering: Kim, Jay, Tom"
print(group_list("Users", "")) # Should be "Users:"

Solution 8:^[8]

def group_list(group, users):
    members = "{}: {}".format(group, ", ".join(users) )
    return members

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution	Source
Solution 1	Abhishek Verma
Solution 2	Martin Brisiak
Solution 3	Deepak Kumar
Solution 4	Queendalin Ezenwa
Solution 5	buddemat
Solution 6	Omar bakhsh
Solution 7	fatboy888
Solution 8	alexpdev

'how to solve: The group_list function accepts a group name and a list of members

Solution 1:[1]

Solution 2:[2]

Solution 3:[3]

Solution 4:[4]

Solution 5:[5]

Solution 6:[6]

Solution 7:[7]

Solution 8:[8]