How to separate contents of item containers?

Question

I am in the process of building an email scraper and am having trouble when it comes to yielding items. My yield prints as:

{'email': ['[email protected]', '[email protected]', '[email protected]']}

Whenever I export this into CSV I have an email header and then the three emails are listed in the same cell. How would I separate these into individual cells?

class EmailSpider(CrawlSpider):
    name = 'emails'
    start_urls = ['https://example.com']

    parsed_url = urlparse(start_urls[0])
    rules = [Rule(LinkExtractor(allow_domains=parsed_url), callback='parse', follow=True)]

    def parse(self, response):
        # Scrape page for email links
        items = EmailscrapeItem()

        hrefs = [response.xpath("//a[starts-with(@href, 'mailto')]/text()").getall()]
        # Removes hrefs that are empty or None
        hrefs = [d for d in hrefs if d]
        # TODO: Add code to capture non-mailto emails as well
        # hrefs.append(response.xpath("//*[contains(text(), '@')]/text()"))

        for href in hrefs:
            items['email'] = href
            yield items

Answer 1

Figured out what I did wrong.

I changed my parse to:

        for res in response.xpath("//a[starts-with(@href, 'mailto')]/text()"):
            item = EmailscrapeItem()
            item['email'] = res.get()
            yield item

This yielded the proper results.