'How to save each row to csv in dataframe AND name the file based on the the first column in each row
I have the following df, with the row 0 being the header:
teacher,grade,subject
black,a,english
grayson,b,math
yodd,a,science
What is the best way to use export_csv in python to save each row to a csv so that the files are named:
black.csv
grayson.csv
yodd.csv
Contents of black.csv will be:
teacher,grade,subject
black,a,english
Thanks in advance!
Updated Code:
df8['CaseNumber'] = df8['CaseNumber'].map(str)
df8.set_index('CaseNumber', inplace=True)
for Casenumber, data in df8.iterrows():
data.to_csv('c:\\users\\admin\\' + Casenumber + '.csv')'''
Solution 1:[1]
This can be done simply by using pandas:
import pandas as pd
# Preempt the issue of columns being numeric by marking dtype=str
df = pd.read_csv('your_data.csv', header=1, dtype=str)
df.set_index('teacher', inplace=True)
for teacher, data in df.iterrows():
data.to_csv(teacher + '.csv')
Edits:
df8.set_index('CaseNumber', inplace=True)
for Casenumber, data in df8.iterrows():
# Use r and f strings to make your life easier:
data.to_csv(rf'c:\users\admin\{Casenumber}.csv')
Sources
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Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 |
