How to returns a list of all values corresponding to keys greater than x in the dictionary [duplicate]

Question

I need to use for For loop to find the return the list of values in a dictionary greater than x.

d= {}
for key in d():
    if key > x:
        return(d(key))

Answer 1

d = dict(a=1, b=10, c=30, d=2)
>>> d
{'a': 1, 'c': 30, 'b': 10, 'd': 2}   

d = dict((k, v) for k, v in d.items() if v >= 10)
>>> d    
{'c': 30, 'b': 10}

values_list = list(d.values())
>>> values_list
[30, 10]

Answer 2

We hold greater_than_x list, and append the values in d dictionary if it's bigger than the given x.

x = 20
greater_than_x = []
d = {"a": 10, "b": 20, "c": 30}


for value in d.values():
    if value > x:
        greater_than_x.append(value)

print(greater_than_x)

>[30]

One-liner applying the same logic:

x = 20
d = {"a": 10, "b": 20, "c": 30}

greater_than_x = [value for value in d.values() if value > x]
print(greater_than_x)

>[30]