how to replace values from a list comprehension? [duplicate]

Question

Im trying to make a list from a string with multiple lines. So every new item in the list will be an entire word, I made it, but I was curious to know if it could be done with list comprehension. Im just a beginner*

list:

listExample = """example1
example2
example3"""

I solved it with:

listE = ['']

for n in listExample:
    if n == '\n':
        listE.insert(0, '')
    else:
        listE[0] = listE[0] + n

del listE[0]
print(listE)

But, is it possible with list comprehension?

Sorry, I messed it up (forget to include the list listE)

Answer 1

Easy solution

This simplest way to get this done is with the str.split() method:

>>> listExample.split()
['example1', 'example2', 'example3']

List comprehension version

A list comprehension would is more circuitous but would also get the job done:

>>> [word for word in listExample.splitlines()]
['example1', 'example2', 'example3']

Answer 2

For some variety, and to show similar syntax as if you were reading a file:

from io import StringIO

listExample = """example1
example2
example3"""

with StringIO(listExample) as f:
    the_list = [x.strip() for x in f]

print(the_list)

Output:

['example1', 'example2', 'example3']

Answer 3

You can add conditional expression to list comprehension to filter elements

For example:

# Exclude word(s) based on index
listE2 = [w for i, w in enumerate(listExample.split()) if i not in [0]]

# Exclude word(s) based on the word
listE3 = [w for w in listExample.split() if w not in ['example3']]