'How to remove the first and the last character of a string

I'm wondering how to remove the first and last character of a string in Javascript.

My url is showing /installers/ and I just want installers.

Sometimes it will be /installers/services/ and I just need installers/services.

So I can't just simply strip the slashes /.

Solution 1:^[1]

Here you go

var yourString = "/installers/";
var result = yourString.substring(1, yourString.length-1);

console.log(result);

Or you can use .slice as suggested by Ankit Gupta

var yourString = "/installers/services/";

var result = yourString.slice(1,-1);

console.log(result);

Documentation for the slice and substring.

Solution 2:^[2]

It may be nicer one to use slice like :

string.slice(1, -1)

Solution 3:^[3]

I don't think jQuery has anything to do with this. Anyway, try the following :

url = url.replace(/^\/|\/$/g, '');

Solution 4:^[4]

If you dont always have a starting or trailing slash, you could regex it. While regexes are slower then simple replaces/slices, it has a bit more room for logic:

"/installers/services/".replace(/^\/?|\/?$/g, "") 

# /installers/services/ -> installers/services
# /installers/services -> installers/services
# installers/services/ -> installers/services

The regex explained:

['start with' ^] + [Optional?] + [slash]: ^/?, escaped -> ^\/?
The pipe ( | ) can be read as or
['ends with' $] + [Optional ?] + [slash] -> /?$, escaped -> \/?$

Combined it would be ^/?|/$ without escaping. Optional first slash OR optional last slash.
^{Technically it isn't "optional", but "zero or one times".}

Solution 5:^[5]

You can do something like that :

"/installers/services/".replace(/^\/+/g,'').replace(/\/+$/g,'')

This regex is a common way to have the same behaviour of the trim function used in many languages.

A possible implementation of trim function is :

function trim(string, char){
    if(!char) char = ' '; //space by default
    char = char.replace(/([()[{*+.$^\\|?])/g, '\\$1'); //escape char parameter if needed for regex syntax.
    var regex_1 = new RegExp("^" + char + "+", "g");
    var regex_2 = new RegExp(char + "+$", "g");
    return string.replace(regex_1, '').replace(regex_2, '');
}

Which will delete all / at the beginning and the end of the string. It handles cases like ///installers/services///

You can also simply do :

"/installers/".substring(1, string.length-1);

Solution 6:^[6]

You can use substring method

s = s.substring(0, s.length - 1) //removes last character

another alternative is slice method

Solution 7:^[7]

if you need to remove the first leter of string

string.slice(1, 0)

and for remove last letter

string.slice(0, -1)

Solution 8:^[8]

use .replace(/.*\/(\S+)\//img,"$1")

"/installers/services/".replace(/.*\/(\S+)\//img,"$1"); //--> services

"/services/".replace(/.*\/(\S+)\//img,"$1"); //--> services

Solution 9:^[9]

url=url.substring(1,url.Length-1);

This way you can use the directories if it is like .../.../.../... etc.

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution	Source
Solution 1	Trott
Solution 2	Penny Liu
Solution 3
Solution 4
Solution 5
Solution 6	Hessam
Solution 7	Rizwan
Solution 8	Victor Ribeiro da Silva Eloy
Solution 9	Kuzgun

'How to remove the first and the last character of a string

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