'How to remove special characters from url?

let ids = [String: [String]]

ids=%5B%4566abef1c-4462-4g62-bcc5-5ae10547104c%22,%20%1256efcf8c-6977-430d-b3ec-4ae80547101c%22%5D

After appended and passing url params, response failing in response structure special symbol added in -> %5B%%

https://baseUrl/endpoint?ids=4566abef1c-4462-4g62-bcc5-5ae10547104c,1256efcf8c-6977-430d-b3ec-4ae80547101c

How to remove %22%5D from url?

Here Code:

let parms: [String: [String]]
let urlString = "\(baseUrl)/\(endpoint)"
Connector.requestSwiftyJson(
    url: urlString,
    requestType: .get,
    withParams: parms,
    loader: false
) { json, response, error in
iosswiftstringurl


Solution 1:[1]

you can remove unwanted characters by adapting the parameters right before passing it into the parser like:

let adaptedParams = params.reduce(into: [String: String]()) { $0[$1.key] = $1.value.joined(separator: ",") }

Solution 2:[2]

"...How to remove %22%5D from url? ". Try this:

 let ids = "%5B%4566abef1c-4462-4g62-bcc5-5ae10547104c%22,%20%1256efcf8c-6977-430d-b3ec-4ae80547101c%22%5D"
 let cleanUrl = ids.replacingOccurrences(of: "%22%5D", with: "")
 print("\n---> cleanUrl: \(cleanUrl) \n")

You can also remove all percent encoding using this:

   if let cleanUrl = ids.replacingOccurrences(of: "%5B", with: "") // [
    .replacingOccurrences(of: "%5D", with: "")  // ]
    .replacingOccurrences(of: "%22", with: "")  // "
    .removingPercentEncoding {  // other encoding
    
    print("\n---> cleanUrl: \(cleanUrl) \n")
}

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1 Mojtaba Hosseini
Solution 2

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