How to print this pyramid pattern up side down?

Question

I am trying to print below pyramid pattern. But not clicking how to build logic for it ?

Pattern :

5 4 3 2 1
  4 3 2 1
    3 2 1 
      2 1
        1 

I have tried this code seems like this is not a right approach to get it.Any solution is appreciated

import numpy as np
n = 5
cnt=0
var = np.arange(1,n+1)
for row in range(1,n+1):
  print(var[::-1][cnt:])
  cnt= cnt + 1

Output of above pattern:

[5 4 3 2 1]
[4 3 2 1]
[3 2 1]
[2 1]
[1]

Answer 1

You can create a function to reduce overall complexity

def pyramid(height):
   L = 0
   for i in range(height):
     s = ' '.join(map(str, range(height-i, 0, -1)))
     L = max(L, len(s))
     print(s.rjust(L))
height = int(input('Enter the height of the Pyramid : '))
pyramid(height)

Answer 2

Any solution? Ok:

>>> print("\n".join([ "{:>10}".format(" ".join([ str(x) for x in range(n,0,-1) ])) for n in range(5,0,-1) ]))
 5 4 3 2 1
   4 3 2 1
     3 2 1
       2 1
         1