How to print separately this type of pair? [closed]

Question

adjacency_list = {
    'A': [('B', 8), ('C', 2), ('D', 14)],
    'B': [('D', 21)],
    'C': [('E', 19)],
    'D': [('E',17), ('F', 13), ('C', 25)],
    'E': [('G', 9), ('F', 5)],
    'F': [('G', 1)]
}
row = adjacency_list.get('F')
for pair in row:
    print(pair)

I have this list, I want to print pair value separately, like CPP. I want to print pair.first and then pair.second. Which will print 'G' first and then 1 instead of printing ('G', 1) together.
How can I do this?

Answer 1

Simple unpacking seems to be enough:

>>> for pair in row:
...     print(*pair)
...
G 1

Answer 2

seems like you have some key value pairs?

adjacency_list = {
    'A': [('B', 8), ('C', 2), ('D', 14)],
    'B': [('D', 21)],
    'C': [('E', 19)],
    'D': [('E',17), ('F', 13), ('C', 25)],
    'E': [('G', 9), ('F', 5)],
    'F': [('G', 1)]
}
row = adjacency_list.get('F')
for key,value in row:
    print("Key: " + str(key) + " Value: " + str(value))

Answer 3

I usually do it like this:

adjacency_list = {
    'A': [('B', 8), ('C', 2), ('D', 14)],
    'B': [('D', 21)],
    'C': [('E', 19)],
    'D': [('E',17), ('F', 13), ('C', 25)],
    'E': [('G', 9), ('F', 5)],
    'F': [('G', 1)]
}
row = adjacency_list.get('F')
for (k, v) in row:
    print(f'{k}{v}')

In the for loop you can name the elements of the pair, and then print using f-strings for string interpolation using the names you bound the elements of the pair to.