How to print every variable from biggest to smallest in python

Question

I'm working on a zif's law project in python. I wrote this code:

import os
my_file = open("words.txt", "r")
content = my_file.read()
w = content.split()
my_file.close()

def split(a):
    return[char for char in a]

x = 0
for i in range(len(w)):
    w[x] = w[x].lower()
    s = split(w[x])

    y = 0
    for i in range(len(s)):
        if s[y] == "." or s[y] == s[y] == "," or s[y] == "'" or s[y] == "0" or s[y] == "1" or s[y] == "2" or s[y] == "3" or s[y] == "4" or s[y] == "5" or s[y] == "6" or s[y] == "7" or s[y] == "8" or s[y] == "9":
            s[y] = ''
        y += 1

    s = "".join(s)
    w[x] = s
    x += 1





o = open("wzl.py", "w")
x = 0
p = 0
for i in range(len(w)):
    if x == (len(w) - 1):
        break
    y = 0
    o.write(f"{w[x]}1 = 1")
    o.write("\n")
    for i in range(len(w) - 1):
        y += 1

        if w[x] == w[y]:
            o.write(f"{w[x]}1 += 1  ")
            o.write("\n")
            del w[y]
            y -= 1



        if y == (len(w) - 1):
            o.write(f"print('{w[x]} = ', {w[x]}1)")
            o.write("\n")
            del w[x]
            x -= 1

    print(w)
    x += 1

o.close()
os.system("python wzl.py")
    

It opens the other file and writes this:

sitting1 = 1
print('sitting = ', sitting1)
in1 = 1
in1 += 1  
print('in = ', in1)
the1 = 1
the1 += 1  
print('the = ', the1)
sun1 = 1
print('sun = ', sun1)
away1 = 1
print('away = ', away1)
from1 = 1
print('from = ', from1)
everyone1 = 1
print('everyone = ', everyone1)
who1 = 1
print('who = ', who1)
had1 = 1
print('had = ', had1)
done1 = 1
print('done = ', done1)
him1 = 1
print('him = ', him1)
harm1 = 1
print('harm = ', harm1)

Now, all I need is for the code to go through every variable and print the first 10 from biggest to smallest, how do I do that? I think i can do it with class but i don't know how to use it.

Also if you find some way I can improve my code, please note.

Input example: 'Sitting in the sun, away from everyone who had done him harm in the past.'

Output example:

the: 6
he: 5
of: 2
she: 1

Answer 1

Actually you can use built-in collections module to do this work for you. Why reinvent the wheel when there is a builtin implementation

from collections import Counter as Co
listofwords = 'Hi Hi a a a for be a hi hi hlo hlo'
print(Co(listofwords.split()))
#Counter({'a': 4, 'Hi': 2, 'hi': 2, 'hlo': 2, 'for': 1, 'be': 1})

# if you want to find the 2 most common words
print(a.most_common(2)) 
#[('a', 4), ('Hi', 2)]

here is an article if you want to read about it