how to print a list inside a function without using append method

Question

k=[]
def subject(a):
     
    for i in range(0,a):
        ele=int(input("number: "))
        k=ele
    print(k)
        
n=int(input("Enter numb of elements: "))
subject(n)
#print(k)

I am not able to print whole list, that user input, please help?

Answer 1

Since you don't want to use append, you should initialize your list with n number of 0's or None. Try this:

def subject(a):
    k = [0 for _ in range(a)]  # Initialise your list with 'n' number of 0's 
    for i in range(0,a):
        ele = int(input("number: "))
        k[i] = ele   # Filling the i'th index of list with user input 
    print(k)
        
n=int(input("Enter numb of elements: "))
subject(n)
#print(k)

Output:

Enter numb of elements: 
3
number: 
1
number: 
2
number: 
3
[1, 2, 3]

Answer 2

This would work just fine as well:

def subject(a):
    k=[]     
    for i in range(a):
        ele = int(input("number: "))
        k += [ele]
    print(k)
        
n = int(input("Enter numb of elements: "))
subject(n)

Answer 3

Alternate for append is by using "+" operand. However, I did with string
Try this too

def subject(a):
    string=""
    for i in range(a):
        string+=input()
        result=[int(x) for x in string]
    return result
n=int(input("Enter a number :")) 
print(subject(n))