How to open external programs in Python

Question

Duplicate edit: no, i did that but it doesnt want to launch firefox. I am making a cortana/siri assistant thing, and I want it to lets say open a web browser when I say something. So I have done the if part, but I just need it to launch firefox.exe I have tried different things and I get an error . Here is the code. Please help! It works with opening notepad but not firefox..

#subprocess.Popen(['C:\Program Files\Mozilla Firefox\firefox.exe']) opens the app and continues the script
#subprocess.call(['C:\Program Files\Mozilla Firefox\firefox.exe']) this opens it but doesnt continue the script

import os
import subprocess

print "Hello, I am Danbot.. If you are new ask for help!" #intro

prompt = ">"     #sets the bit that indicates to input to >

input = raw_input (prompt)      #sets whatever you say to the input so bot can proces

raw_input (prompt)     #makes an input


if input == "help": #if the input is that
 print "*****************************************************************" #says that
 print "I am only being created.. more feautrues coming soon!" #says that
 print "*****************************************************************" #says that
 print "What is your name talks about names" #says that
 print "Open (name of program) opens an application" #says that
 print "sometimes a command is ignored.. restart me then!"
 print "Also, once you type in a command, press enter a couple of times.."
 print "*****************************************************************" #says that

raw_input (prompt)     #makes an input

if input == "open notepad": #if the input is that
 print "opening notepad!!" #says that
 print os.system('notepad.exe') #starts notepad

if input == "open the internet": #if the input is that
 print "opening firefox!!" #says that
 subprocess.Popen(['C:\Program Files\Mozilla Firefox\firefox.exe'])

Answer 1

The short answer is that os.system doesn't know where to find firefox.exe.

A possible solution would be to use the full path. And it is recommended to use the subprocess module:

import subprocess

subprocess.call(['C:\Program Files\Mozilla Firefox\\firefox.exe'])

Mind the \\ before the firefox.exe! If you'd use \f, Python would interpret this as a formfeed:

>>> print('C:\Program Files\Mozilla Firefox\firefox.exe')
C:\Program Files\Mozilla Firefox
                                irefox.exe

And of course that path doesn't exist. :-)

So either escape the backslash or use a raw string:

>>> print('C:\Program Files\Mozilla Firefox\\firefox.exe')
C:\Program Files\Mozilla Firefox\firefox.exe
>>> print(r'C:\Program Files\Mozilla Firefox\firefox.exe')
C:\Program Files\Mozilla Firefox\firefox.exe

Note that using os.system or subprocess.call will stop the current application until the program that is started finishes. So you might want to use subprocess.Popen instead. That will launch the external program and then continue the script.

subprocess.Popen(['C:\Program Files\Mozilla Firefox\\firefox.exe', '-new-tab'])

This will open firefox (or create a new tab in a running instance).

---

A more complete example is my open utility I publish via github. This uses regular expressions to match file extensions to programs to open those files with. Then it uses subprocess.Popen to open those files in an appropriate program. For reference I'm adding the complete code for the current version below.

Note that this program was written with UNIX-like operating systems in mind. On ms-windows you could probably get an application for a filetype from the registry.

"""Opens the file(s) given on the command line in the appropriate program.
Some of the programs are X11 programs."""

from os.path import isdir, isfile
from re import search, IGNORECASE
from subprocess import Popen, check_output, CalledProcessError
from sys import argv
import argparse
import logging

__version__ = '1.3.0'

# You should adjust the programs called to suit your preferences.
filetypes = {
    '\.(pdf|epub)$': ['mupdf'],
    '\.html$': ['chrome', '--incognito'],
    '\.xcf$': ['gimp'],
    '\.e?ps$': ['gv'],
    '\.(jpe?g|png|gif|tiff?|p[abgp]m|svg)$': ['gpicview'],
    '\.(pax|cpio|zip|jar|ar|xar|rpm|7z)$': ['tar', 'tf'],
    '\.(tar\.|t)(z|gz|bz2?|xz)$': ['tar', 'tf'],
    '\.(mp4|mkv|avi|flv|mpg|movi?|m4v|webm)$': ['mpv']
}
othertypes = {'dir': ['rox'], 'txt': ['gvim', '--nofork']}


def main(argv):
    """Entry point for this script.

    Arguments:
        argv: command line arguments; list of strings.
    """
    if argv[0].endswith(('open', 'open.py')):
        del argv[0]
    opts = argparse.ArgumentParser(prog='open', description=__doc__)
    opts.add_argument('-v', '--version', action='version',
                      version=__version__)
    opts.add_argument('-a', '--application', help='application to use')
    opts.add_argument('--log', default='warning',
                      choices=['debug', 'info', 'warning', 'error'],
                      help="logging level (defaults to 'warning')")
    opts.add_argument("files", metavar='file', nargs='*',
                      help="one or more files to process")
    args = opts.parse_args(argv)
    logging.basicConfig(level=getattr(logging, args.log.upper(), None),
                        format='%(levelname)s: %(message)s')
    logging.info('command line arguments = {}'.format(argv))
    logging.info('parsed arguments = {}'.format(args))
    fail = "opening '{}' failed: {}"
    for nm in args.files:
        logging.info("Trying '{}'".format(nm))
        if not args.application:
            if isdir(nm):
                cmds = othertypes['dir'] + [nm]
            elif isfile(nm):
                cmds = matchfile(filetypes, othertypes, nm)
            else:
                cmds = None
        else:
            cmds = [args.application, nm]
        if not cmds:
            logging.warning("do not know how to open '{}'".format(nm))
            continue
        try:
            Popen(cmds)
        except OSError as e:
            logging.error(fail.format(nm, e))
    else:  # No files named
        if args.application:
            try:
                Popen([args.application])
            except OSError as e:
                logging.error(fail.format(args.application, e))


def matchfile(fdict, odict, fname):
    """For the given filename, returns the matching program. It uses the `file`
    utility commonly available on UNIX.

    Arguments:
        fdict: Handlers for files. A dictionary of regex:(commands)
            representing the file type and the action that is to be taken for
            opening one.
        odict: Handlers for other types. A dictionary of str:(arguments).
        fname: A string containing the name of the file to be opened.

    Returns: A list of commands for subprocess.Popen.
    """
    for k, v in fdict.items():
        if search(k, fname, IGNORECASE) is not None:
            return v + [fname]
    try:
        if b'text' in check_output(['file', fname]):
            return odict['txt'] + [fname]
    except CalledProcessError:
        logging.warning("the command 'file {}' failed.".format(fname))
        return None


if __name__ == '__main__':
    main(argv)

Answer 2

If you want to open Google or something on the web just import webbrowser and open the URL. I will give you a quick example.

import webbrowser

webbrowser.open("www.google.com")

Answer 3

You can open any program like this:

import subprocess

subprocess.call(['C:\Program Files\Fortnite\fortnite.exe'])

But here's How to find the .exe of any program (Windows only)

I know how to find the .exe file on windows only

To find the .exe file you can click the windows icon.

Then write the name of the application, then right-click on the icon that appears and select 'open file location'.

Then you'll probably be taken to a folder that has one thing and that one thing will have the icon of the file you're looking for. Right-click on it and select 'open file location' again.

You'll be taken to a folder full of stuff. Look for something with the file's icon that you're looking for. Right-click on it and choose copy as path. And that's the path of the file.

Thanks.