How to one-string code write to multi-strings

Question

I am a new to python. I have a dictonary and a list. like this:

dict1 = {'[email protected]': 'John Smith', '[email protected]': 'James Brown'}
list1 = ['[email protected]', '[email protected]', '[email protected]']

I need to compare email from the list with key from dictonary, if it's the same, then print value from dictonary.

I found a great decision:

result = {k:dict1[k] for k in list1 if k in dict1}

It's returns dictonary.

But how to rewrite this in multiline view? I need to add: elif value from list1 != key from dict1 then print value from list1.

Answer 1

Without a comprehension:

for email in list1:
    if email not in dict1:
        print(email)

# Output
[email protected]

Or with a comprehension:

print(*[email for email in list1 if email not in dict1], sep='\n')

# Output
[email protected]

Answer 2

How about this one liner?

dict1 = {'[email protected]': 'John Smith', '[email protected]': 'James Brown'}
list1 = ['[email protected]', '[email protected]', '[email protected]']
print('\n'.join(list(filter(lambda x:x not in dict1,list1))))

output:

[email protected]

Answer 3

Get a list of emails not found in dict1 using list comprehension:

not_found = [i for i in list1 if i not in dict1]

You can run for loop on this "not_found" var.

Answer 4

You will have a better control over your data processing if you convert your dict comprehension into a classical for-loop like so:

results = {}
for k in list1: 
   if k in dict1: 
      results[k] = dict1[k] 
   else:
      results[k] = "no name" 
      print(k)