how to jump a list member in python?

Question

so I'm trying to send i message to a group of people . I want to know how can I jump to 'test2' (next list member ) if 'test1' (current list member ) got an error .

profile_id = ['test1','test2']
for ids in profile_id:
    api.send_direct_message(ids,text)

Answer 1

as Menashe already said, you can use TRY, EXCEPT and PASS. like this:

profile_id = ['test1','test2']
for ids in profile_id:
    try:
       api.send_direct_message(ids,text)
    except:
       pass

Answer 2

for iterates trough iprofile_id. So, the variable ids will first be the element 'test 1', do whatever is inside the for loop (i.e., send message to the person that is called 'test 1'. Then ids becomes 'test2', and a message is sent to 'test2'. But you try sending a message to the list of people, not the person picked (ids). I assume that the function send_direct_message does not allow lists, so therefore you need to have your third line be api.send_direct_message(ids, text).

Answer 3

Why not use TRY and then EXCEPT for the relevant class?

You can then use PASS to do nothing and continue to the next.

Answer 4

You can try to use try/except for that, but only in a case if you raise an exception in send_direct_message

profile_ids = ['test1','test2']
for index, profile_id in enumerate(profile_ids):
    try:
        api.send_direct_message(profile_id,text)
    # assume that using just Exception is not a good tone, try to use specific exception you raise in the method here instead of just Exception
    except Exception as exc:
        if (index+1) >= len(profile_ids):
            break
        api.send_direct_message(profile_ids[index+1], text)
        # but in such a case think of list index out of range error, that will be thrown when list will go to an end