'How to get user id from email address in Microsoft Graph API C#

I want to add User to a Group but I don't have the User's id, I only have the email address.

Here is the code:

User userToAdd = await graphClient
    .Users["objectID"]
    .Request()
    .GetAsync();

await graphClient
    .Groups["groupObjectID"]
    .Members
    .References
    .Request()
    .AddAsync(userToAdd);

Can someone help how do I retrieve ObjectId (User ID) from an email address using Microsoft Graph?

c++sharpmicrosoft-graph-api


Solution 1:[1]

You can look up a user a few different ways.

From the /users endpoint you can either use their id (the GUID assigned to each account) or their userPrincipalName (their email alias for the default domain):

// Retrieve a user by id
var user  = await graphClient
    .Users["00000000-0000-0000-0000-000000000000"]
    .Request()
    .GetAsync();

// Retrieve a user by userPrincipalName
var user  = await graphClient
    .Users["[email protected]"]
    .Request()
    .GetAsync();

If you're using either the Authorization Code or Implicit OAuth grants, you can also look up the user who authenticated via the /me endpoint:

var user = await graphClient
    .Me
    .Request()
    .GetAsync();

Solution 2:[2]

Besides these correct answers above.

userPrincipalName or id is not the external email address. That was my case when registration is done manually. You can use this filter:

var user = await _graphClient.Users
    .Request()
    .Filter($"identities/any(c:c/issuerAssignedId eq '{email}' and c/issuer eq 'contoso.onmicrosoft.com')")
    .GetAsync();

src: https://docs.microsoft.com/en-us/graph/api/user-list?view=graph-rest-1.0&tabs=csharp

Using this configuration to create an user:

Microsoft.Graph.User graphUser = new Microsoft.Graph.User
{
    AccountEnabled = true,
    PasswordPolicies = "DisablePasswordExpiration,DisableStrongPassword",
    PasswordProfile = new PasswordProfile
    {
            ForceChangePasswordNextSignIn = false,
            Password = accountModel.Password,
        },
        Identities = new List<ObjectIdentity>
        {
            new ObjectIdentity()
            {
                SignInType = "emailAddress",
                Issuer ="contoso.onmicrosoft.com",
                IssuerAssignedId = email
            }
        },
};

Solution 3:[3]

You can retrieve user's details from Graph API using id or userPrincipalName (which is an email address).

From Microsoft Graph API reference:

GET /users/{id | userPrincipalName}

Have you tried to use the email address as objectID?

Solution 4:[4]

If you need retrieve a guest user may use:

public static async Task<User> GetGuestUserByEmail(string email)
{
        try
        {
            var request = await graphClient
                .Users
                .Request()
                .Filter($"userType eq 'guest' and mail eq '{email}'") // apply filter
                .GetAsync();

            var guestUsers = request.CurrentPage.ToList();
            var user = guestUsers.FirstOrDefault();
            return user;
        }
        catch (ServiceException ex)
        {
            Console.WriteLine($"Error: {ex.Message}");
            return null;
        }
 }

Solution 5:[5]

There actually is no truly reliable way to do this. Email addresses in AAD are not unique. The UPN is often an email address, and it is unique, but there's a nasty catch: If the person happens to have a long email address AND they're a guest user, the UPN appears to be the email truncated to 54 characters, then have #EXT# tacked on, and it can even be changed after the fact to have the #EXT# removed where it can be up to 64 characters before the @ symbol, and doesn't have to be anything resembling their actual email address.

The only way you're supposed to actually be able to find them is with their user object's GUID.

https://docs.microsoft.com/en-us/answers/questions/81053/user-principal-name-and-ext.html

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1 Marc LaFleur
Solution 2 Sachin Joseph
Solution 3
Solution 4 LuisEduardox
Solution 5 Dragoon

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