How to get URI from an asset File?

Question

I have been trying to get the URI path for an asset file.

uri = Uri.fromFile(new File("//assets/mydemo.txt"));

When I check if the file exists I see that file doesn't exist

File f = new File(filepath);
if (f.exists() == true) {
    Log.e(TAG, "Valid :" + filepath);
} else {
    Log.e(TAG, "InValid :" + filepath);
}

Can some one tell me how I can mention the absolute path for a file existing in the asset folder

Answer 1

The correct url is:

file:///android_asset/RELATIVEPATH

where RELATIVEPATH is the path to your resource relative to the assets folder.

Note the 3 /'s in the scheme. Web view would not load any of my assets without the 3. I tried 2 as (previously) commented by CommonsWare and it wouldn't work. Then I looked at CommonsWare's source on github and noticed the extra forward slash.

This testing though was only done on the 1.6 Android emulator but I doubt its different on a real device or higher version.

EDIT: CommonsWare updated his answer to reflect this tiny change. So I've edited this so it still makes sense with his current answer.

Answer 2

Finally, I found a way to get the path of a file which is present in assets from this answer in Kotlin. Here we are copying the assets file to cache and getting the file path from that cache file.

@Throws(IOException::class)
    fun getFileFromAssets(context: Context, fileName: String): File = File(context.cacheDir, fileName)
            .also {
               if (!it.exists()) {
                it.outputStream().use { cache ->
                    context.assets.open(fileName).use { inputStream ->
                            inputStream.copyTo(cache)
                    }
                  }
                }
            }

Get the path to the file like:

val filePath =  getFileFromAssets(context, "fileName.extension").absolutePath

Answer 3

Please try this code working fine

 Uri imageUri = Uri.fromFile(new File("//android_asset/luc.jpeg"));

    /* 2) Create a new Intent */
    Intent imageEditorIntent = new AdobeImageIntent.Builder(this)
            .setData(imageUri)
            .build();

Answer 4

Be sure ,your assets folder put in correct position.

Answer 5

Works for WebView but seems to fail on URL.openStream(). So you need to distinguish file:// protocols and handle them via AssetManager as suggested.

Answer 6

Try this out, it works:

InputStream in_s = 
    getClass().getClassLoader().getResourceAsStream("TopBrands.xml");

If you get a Null Value Exception, try this (with class TopBrandData):

InputStream in_s1 =
    TopBrandData.class.getResourceAsStream("/assets/TopBrands.xml");

Answer 7

InputStream is = getResources().getAssets().open("terms.txt");
String textfile = convertStreamToString(is);
    
public static String convertStreamToString(InputStream is)
        throws IOException {

    Writer writer = new StringWriter();
    char[] buffer = new char[2048];

    try {
        Reader reader = new BufferedReader(new InputStreamReader(is, "UTF-8"));
        int n;
        while ((n = reader.read(buffer)) != -1) {
            writer.write(buffer, 0, n);
        }
    } finally {
        is.close();
    }

    String text = writer.toString();
    return text;
}

Answer 8

try this :

Uri uri = Uri.parse("android.resource://"+getPackageName()+"/"+R.raw.cat); 

I had did it and it worked

Answer 9

Yeah you can't access your drive folder from you android phone or emulator because your computer and android are two different OS.I would go for res folder of android because it has good resources management methods. Until and unless you have very good reason to put you file in assets folder. Instead You can do this

try {
      Resources res = getResources();
      InputStream in_s = res.openRawResource(R.raw.yourfile);

      byte[] b = new byte[in_s.available()];
      in_s.read(b);
      String str = new String(b);
    } catch (Exception e) {
      Log.e(LOG_TAG, "File Reading Error", e);
 }

Answer 10

If you are okay with not using assets folder and want to get a URI without storing it in another directory, you can use res/raw directory and create a helper function to get the URI from resID:

internal fun Context.getResourceUri(@AnyRes resourceId: Int): Uri =
    Uri.Builder()
        .scheme(ContentResolver.SCHEME_ANDROID_RESOURCE)
        .authority(packageName)
        .path(resourceId.toString())
        .build()

Now if you have a mydemo.txt file under res/raw directory you can simply get the URI by calling the above helper method

context.getResourceUri(R.raw.mydemo)

Reference: https://stackoverflow.com/a/57719958