'How to get latest offset for a partition for a kafka topic?

I am using the Python high level consumer for Kafka and want to know the latest offsets for each partition of a topic. However I cannot get it to work.

from kafka import TopicPartition
from kafka.consumer import KafkaConsumer

con = KafkaConsumer(bootstrap_servers = brokers)
ps = [TopicPartition(topic, p) for p in con.partitions_for_topic(topic)]

con.assign(ps)
for p in ps:
    print "For partition %s highwater is %s"%(p.partition,con.highwater(p))

print "Subscription = %s"%con.subscription()
print "con.seek_to_beginning() = %s"%con.seek_to_beginning()

But the output I get is

For partition 0 highwater is None
For partition 1 highwater is None
For partition 2 highwater is None
For partition 3 highwater is None
For partition 4 highwater is None
For partition 5 highwater is None
....
For partition 96 highwater is None
For partition 97 highwater is None
For partition 98 highwater is None
For partition 99 highwater is None
Subscription = None
con.seek_to_beginning() = None
con.seek_to_end() = None

I have an alternate approach using assign but the result is the same

con = KafkaConsumer(bootstrap_servers = brokers)
ps = [TopicPartition(topic, p) for p in con.partitions_for_topic(topic)]

con.assign(ps)
for p in ps:
    print "For partition %s highwater is %s"%(p.partition,con.highwater(p))

print "Subscription = %s"%con.subscription()
print "con.seek_to_beginning() = %s"%con.seek_to_beginning()
print "con.seek_to_end() = %s"%con.seek_to_end()

It seems from some of the documentation that I might get this behaviour if a fetch has not been issued. But I cannot find a way to force that. What am I doing wrong?

Or is there a different/simpler way to get the latest offsets for a topic?



Solution 1:[1]

If you wish to use Kafka shell scripts present in kafka/bin, then you can get latest and smallest offsets by using kafka-run-class.sh.

To get latest offset command will look like this

bin/kafka-run-class.sh kafka.tools.GetOffsetShell --broker-list localhost:9092 --time -1 --topic topiname

To get smallest offset command will look like this

bin/kafka-run-class.sh kafka.tools.GetOffsetShell --broker-list localhost:9092 --time -2 --topic topiname

You can find more information on Get Offsets Shell from following link

Hope this helps!

Solution 2:[2]

from kafka import KafkaConsumer, TopicPartition

TOPIC = 'MYTOPIC'
GROUP = 'MYGROUP'
BOOTSTRAP_SERVERS = ['kafka01:9092', 'kafka02:9092']

consumer = KafkaConsumer(
        bootstrap_servers=BOOTSTRAP_SERVERS,
        group_id=GROUP,
        enable_auto_commit=False
    )


for p in consumer.partitions_for_topic(TOPIC):
    tp = TopicPartition(TOPIC, p)
    consumer.assign([tp])
    committed = consumer.committed(tp)
    consumer.seek_to_end(tp)
    last_offset = consumer.position(tp)
    print("topic: %s partition: %s committed: %s last: %s lag: %s" % (TOPIC, p, committed, last_offset, (last_offset - committed)))

consumer.close(autocommit=False)

Solution 3:[3]

With kafka-python>=1.3.4 you can use:

kafka.KafkaConsumer.end_offsets(partitions)

Get the last offset for the given partitions. The last offset of a partition is the offset of the upcoming message, i.e. the offset of the last available message + 1.

from kafka import TopicPartition
from kafka.consumer import KafkaConsumer

con = KafkaConsumer(bootstrap_servers = brokers)
ps = [TopicPartition(topic, p) for p in con.partitions_for_topic(topic)]

con.end_offsets(ps)

Solution 4:[4]

Another way to achieve this is by polling the consumer to obtain the last consumed offset and then using the seek_to_end method to obtain the most recent available offset partition.

from kafka import KafkaConsumer
consumer = KafkaConsumer('my-topic',
                     group_id='my-group',
                     bootstrap_servers=['localhost:9092'])
consumer.poll()
consumer.seek_to_end()

This method particularly comes in handy when using consumer groups.

SOURCES:

  1. https://kafka-python.readthedocs.io/en/master/apidoc/kafka.consumer.html#kafka.consumer.KafkaConsumer.poll
  2. https://kafka-python.readthedocs.io/en/master/apidoc/kafka.consumer.html#kafka.consumer.KafkaConsumer.seek_to_end

Solution 5:[5]

Using confluent-kafka-python

You can use position:

Retrieve current positions (offsets) for the list of partitions.

from confluent_kafka import Consumer, TopicPartition


consumer = Consumer({"bootstrap.servers": "localhost:9092"})
topic = consumer.list_topics(topic='topicName')
partitions = [TopicPartition('topicName', partition) for partition in list(topic.topics['topicName'].partitions.keys())] 

offset_per_partition = consumer.position(partitions)

Alternatively, you can also use get_watermark_offsets but you'd have to pass one partition at a time and thus it requires multiple calls:

Retrieve low and high offsets for partition.

from confluent_kafka import Consumer, TopicPartition


consumer = Consumer({"bootstrap.servers": "localhost:9092"})
topic = consumer.list_topics(topic='topicName')
partitions = [TopicPartition('topicName', partition) for partition in list(topic.topics['topicName'].partitions.keys())] 

for p in partitions:
    low_offset, high_offset = consumer.get_watermark_offsets(p)
    print(f"Latest offset for partition {p}: {high_offset}")

Using kafka-python

You can use end_offsets:

Get the last offset for the given partitions. The last offset of a partition is the offset of the upcoming message, i.e. the offset of the last available message + 1.

This method does not change the current consumer position of the partitions.

from kafka import TopicPartition
from kafka.consumer import KafkaConsumer


consumer = KafkaConsumer(bootstrap_servers = "localhost:9092" )
partitions= = [TopicPartition('myTopic', p) for p in consumer.partitions_for_topic('myTopic')]
last_offset_per_partition = consumer.end_offsets(partitions)

Solution 6:[6]

kafka-consumer-groups --bootstrap-server host1:9093,crow-host2:9093,host3:9093 --command-config=/root/client.properties --describe --group atlas

This command will show the status. Lag/offset

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1 Saket
Solution 2 Itamar Lavender
Solution 3 a.costa
Solution 4 olujedai
Solution 5
Solution 6 PANDURANG BHADANGE