How to get attribute value of an element in Playwright Python

Question

I'm using Playwright Python for a project. I'm trying to get the 'href' attribute value of an element.

For Selenium, I used

el = driver.find_element_by_xpath("//a")
link = el.get_attribute('href')

What is the equivalent to the above code in Playwright?

Answer 1

You can access the href in an almost similar way to that of selenium.

element_handle = page.locator("//a")
link = element_handle.get_attribute('href')

Answer 2

You can try to use this code to obtain and print all the hrefs elements of a page. Empty field if it doesn't exist. I'm sure that then, you can obtain the element that you need

const urls = await page.$$eval('a', (elements) =>
   elements.map((el) => el.href),
   )
for await (const u of urls) {
   console.log("URLS: " + u)
}