'How to find the mean and the variance in assembly from an unsigned integer into a floating-point number/decimal

Here is the code that I have below:

INCLUDE Irvine32.inc
.386
.model flat, stdcall
.stack 4096
ExitProcess proto, dwExitCode:dword


PWORD TYPEDEF PTR WORD


.data

RAW WORD 10, 12 , 8, 17, 9, 22, 18, 11, 23, 7, 30, 22, 19, 60, 71
ptr1 PWORD RAW
TEXT1 BYTE "Mean: ", 0
TEXT2 BYTE "Variance: ", 0





TOTAL WORD LENGTHOF RAW
SUM DWORD 0
MEAN DWORD 0
VARSUM DWORD 0





.code
main proc
    mov eax, 0
    mov ecx, LENGTHOF RAW 
    mov esi, OFFSET RAW
    

    SumLoop:
        mov esi,ptr1
        add eax, [esi]
        add esi, TYPE RAW
        loop SumLoop
    
    ; Taking the avg of the numbers
    mov SUM, eax
    cdq
    mov ebx, 15
    div ebx
    mov MEAN, eax
    

    
    





    
    
    

    


    

    invoke ExitProcess, 0

main endp
end main

The question I have is that I am trying to get the mean and the variance from an unsigned integer into a floating-point number/decimal(Format: Mean:XX and Variance:YY). I'm not sure how I'm supposed to do this.

assemblymeanvarianceunsigned-integerfloating-point-conversion


Solution 1:[1]

Integer division will give you an integer quotient and integer remainder.

If you want a mean with decimal places, convert the sum and count to floating point before dividing — then use floating point division to get a floating point answer. 

For example, in C:

float answer = (float) sum / (float) 15;

A compiler can show you the instructions to use.  (You may have to pick a different compiler and/or compiler options for your environment.)

Sources

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Source: Stack Overflow

Solution Source
Solution 1

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