How to find the count of different values for same key

Question

Dict = [{'type':'a','no':'1'},{'type':'b','no':'2'},{'type':'b','no':'3'},{'type':'a','no':'4'},{'type':'c','no':'5'},{'type':'a','no':'6'}]

I need the count of values in type, Output as follows

a = 3
b = 2 
c = 1 

Answer 1

from collections import Counter
Dict = [{'type':'a'},{'type':'b'},{'type':'b'},{'type':'a'},{'type':'c'},{'type':'a'}]

lst = [v for a in Dict for k,v in a.items() if k=='type']


Dict = Counter(lst)
for k,v in Dict.items():
    print(f'{k} = {v}')

OUTPUT

a = 3
b = 2
c = 1

Answer 2

You can use an intermediate dictionary or even import Counter from the collections module. Here's how you could do it without any additional import:

Dict = [{'type':'a','no':'1'},{'type':'b','no':'2'},{'type':'b','no':'3'},{'type':'a','no':'4'},{'type':'c','no':'5'},{'type':'a','no':'6'}]
result = dict()
for d in Dict:
    result[d['type']] = result.get(d['type'], 0) + 1
for k, v in result.items():
    print(f'{k} = {v}')