'How to draw a circle in PyGame?
Hi I am having a problem with drawing a circle ERROR: module object has no attribute 'circle'. what am I doing wrong?
And also how can I put numbers in circles?
For example: (first click is circle with 0 second is circle with 1 and so on)
import pygame
WHITE = (255, 255, 255)
BLUE = ( 0, 0, 255)
GREEN = ( 0, 255, 0)
RED = (255, 0, 0)
TEXTCOLOR = ( 0, 0, 0)
(width, height) = (200, 300)
running = True
def main():
global running, screen
pygame.init()
screen = pygame.display.set_mode((width, height))
pygame.display.set_caption("TUFF")
screen.fill(background_color)
pygame.display.update()
while running:
ev = pygame.event.get()
for event in ev:
if event.type == pygame.MOUSEBUTTONUP:
draw_circle()
pygame.display.update()
if event.type == pygame.QUIT:
running = False
def get_pos():
pos = pygame.mouse.get_pos()
return (pos)
def draw_circle():
pos=get_pos()
pygame.draw.circle(screen, BLUE, pos, 20)
if __name__ == '__main__':
main()
Solution 1:[1]
You've mistyped the name of the function. The correct name is pygame.draw.circle.
def drawCircle():
pos=getPos()
pygame.draw.circle(screen, BLUE, pos, 20) # Here <<<
Solution 2:[2]
Here is how you can draw a circle in pygame;
import pygame
pygame.init()
screen = pygame.display.set_mode((x, y)) #x and y are height and width
pygame.draw.circle(screen, (r,g,b), (x, y), R, w) #(r, g, b) is color, (x, y) is center, R is radius and w is the thickness of the circle border.
Solution 3:[3]
Here is how you can draw a circle properly
import pygame
window = pygame.display.set_mode((500,500))
red = (200,0,0)
circleX = 100
circleY = 100
radius = 10
active = True
while active:
for event in pygame.event.get():
if event.type == pygame.QUIT:
active = False
pygame.draw.circle(window,red,(circleX,circleY),radius) # DRAW CIRCLE
pygame.display.update()
Solution 4:[4]
Mainter a counter for the number of circles you have drawn and write the number with the co-ordinates same as the centre of the circle. Also the command is pygame.draw.circle and not pygame.draw.circl
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Ericson Willians |
| Solution 2 | |
| Solution 3 | Rahul Reghunath |
| Solution 4 | Arijit Sur |
