'How to do an else (default) in match-case?
Python recently has released match-case in version 3.10. The question is how can we do a default case in Python? I can do if/elif but don't know how to do else. Below is the code:
x = "hello"
match x:
case "hi":
print(x)
case "hey":
print(x)
default:
print("not matched")
I added this default myself. I want to know the method to do this in Python.
Solution 1:[1]
match subject:
case <pattern_1>:
<action_1>
case <pattern_2>:
<action_2>
case <pattern_3>:
<action_3>
case _:
<action_wildcard>
cf: https://docs.python.org/3.10/whatsnew/3.10.html#syntax-and-operations
Solution 2:[2]
for thing in [[1,2],[2,11],[12,14,13],[10],[10,20,30,40,50]]:
match thing:
case [x]:
print(f"single value: {x}")
case [x,y]:
print(f"two values: {x} and {y}")
case [x,y,z]:
print(f"three values: {x}, {y} and {z}")
case _: # change this in default
print("too many values")
If you want to read and get more understanding: https://towardsdatascience.com/pattern-matching-in-python-3-10-6124ff2079f0
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Julien Sorin |
| Solution 2 |
