How to display even Fibonacci numbers by specifying their number?

Question

I have a function that checks Fibonacci numbers for even.

def fibonacci(num=4):
    fib1 = fib2 = 1
    print(0, end=' ')
    for i in range(1, num):
        fib1, fib2 = fib2, fib1 + fib2
        if (fib2 % 2) == 0:
            print(fib2, end=' ')

fibonacci()

I need it to output a specified number of even numbers

Example input: 4

Example output: 0 2 8 34

Answer 1

You could make your fibonacci function a generator that only yields even Fibonacci numbers, and then just pull the desired number of values from it:

def even_fibonacci():
    fib1, fib2 = 0, 1
    while True:
        if fib1 % 2 == 0:
            yield fib1
        fib1, fib2 = fib2, fib1 + fib2


it = even_fibonacci()
for _ in range(4):
    print(next(it))

prints:

0
2
8
34

Answer 2

Use while loop instead.

def fibonacci(count=4):
    fib1 = fib2 = 1
    i = 1
    print(0, end=' ')
    while i < count:
        fib1, fib2 = fib2, fib1 + fib2
        if (fib2 % 2) == 0:
            print(fib2, end=' ')
            i +=1

fibonacci()

Output: 0 2 8 34