'How to create a function which displays a specific plot depending on user input in R?
I have a collection of plots, in this example I'll just be using the following for simplicity:
library(tidyverse)
library(ggplot2)
iris <- ggplot(iris, aes(Sepal.Width, Sepal.Length, colour = Species)) +
geom_point(size = 3)
mpg <- ggplot(mpg, aes(manufacturer, fill = manufacturer)) + geom_bar() +
theme(axis.text.x = element_text(angle = 45, hjust = 1))
I would like to create a function called show_plot() which disaplys the iris plot when show_plot(plot_name = "iris") is run and displays the mpg plot when show_plot(plot_name = "mpg) is run.
I know that I would start my function with the following:
show_plot <- function(plot_name){
}
But I really don't know where to go on from here. Would be great if someone could provide some suggestions :)
Solution 1:[1]
You can get the plot object inside the function with get as follows.
# 1- Function
show_plot <- function(plot_name){
return(get(plot_name))
}
# 2- Display the plot
show_plot(plot_name="iris")
This would also require that you have created upstream the mpg and iris objects.
Solution 2:[2]
You can use this code:
library(tidyverse)
library(ggplot2)
iris <- ggplot(iris, aes(Sepal.Width, Sepal.Length, colour = Species)) +
geom_point(size = 3)
mpg <- ggplot(mpg, aes(manufacturer, fill = manufacturer)) + geom_bar() +
theme(axis.text.x = element_text(angle = 45, hjust = 1))
show_plot <- function(plot_name) {
return(get(plot_name))
}
show_plot("mpg")
Output for mpg:
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Yacine Hajji |
| Solution 2 | Quinten |

