How to convert Curl to Python request code?

Question

I want to make a curl to python converter.

curl -X POST -H "data1:value1" -H "data2:value2" -d "{"datapart1":"random1","datapart2":"random2"}" "https://example.com"'

And i want to convert:

import requests

url = 'https://example.com'

data = '{"datapart1":"random1","datapart2":"random2"}'

headers = {'data1': 'value1', 'data2': 'value2'}

r = requests.post(url, data=data, headers=headers)
print(r.text)

Answer 1

I think you want this https://formatter.xyz/curl-to-python-converter

you try it that