'How to check if input looks like an email address and then activate submit button?
I use the following code to check if all form fields are not empty before the submit button is activated.
<script type="text/javascript">
function checkForm() {
var cansubmit = false;
$('form input[type="text"]').each(function (index, element) {
if (element.value == "") {
cansubmit = true;
}
});
document.getElementById("uploadButton").disabled = cansubmit;
}
</script>
How can I edit this code so it checks if the email field contains an email address before the submit button is activated?
UPDATE
I changed the code to this and it seems to work. It checks if it contains @ (and not as the first symbol) and . (and not as the third symbol).
Is this a logical code or should it be easier?
<script type="text/javascript">
function checkForm() {
var cansubmit = false;
$('form input[type="text"]').each(function (index, element) {
if (element.value == "") {
cansubmit = true;
}
});
$('form input[type="email"]').each(function (index, element) {
if (element.value.indexOf("@") <= 0) {
cansubmit = true;
}
else if (element.value.indexOf(".") <= 2) {
cansubmit = true;
}
});
document.getElementById("uploadButton").disabled = cansubmit;
}
</script>
Solution 1:[1]
Use a combination of <input type="email"> and inputElement.validity to check if the input is valid. Docs
Solution 2:[2]
You can use a regex from this answer to validate email address:
if ((element.value == "" && element.type != "email") || (element.type == "email" && !/([!#-'*+/-9=?A-Z^-~-]+(\.[!#-'*+/-9=?A-Z^-~-]+)*|"([]!#-[^-~ \t]|(\\[\t -~]))+")@([0-9A-Za-z]([0-9A-Za-z-]{0,61}[0-9A-Za-z])?(\.[0-9A-Za-z]([0-9A-Za-z-]{0,61}[0-9A-Za-z])?)*|\[((25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9]?[0-9])(\.(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9]?[0-9])){3}|IPv6:((((0|[1-9A-Fa-f][0-9A-Fa-f]{0,3}):){6}|::((0|[1-9A-Fa-f][0-9A-Fa-f]{0,3}):){5}|[0-9A-Fa-f]{0,4}::((0|[1-9A-Fa-f][0-9A-Fa-f]{0,3}):){4}|(((0|[1-9A-Fa-f][0-9A-Fa-f]{0,3}):)?(0|[1-9A-Fa-f][0-9A-Fa-f]{0,3}))?::((0|[1-9A-Fa-f][0-9A-Fa-f]{0,3}):){3}|(((0|[1-9A-Fa-f][0-9A-Fa-f]{0,3}):){0,2}(0|[1-9A-Fa-f][0-9A-Fa-f]{0,3}))?::((0|[1-9A-Fa-f][0-9A-Fa-f]{0,3}):){2}|(((0|[1-9A-Fa-f][0-9A-Fa-f]{0,3}):){0,3}(0|[1-9A-Fa-f][0-9A-Fa-f]{0,3}))?::(0|[1-9A-Fa-f][0-9A-Fa-f]{0,3}):|(((0|[1-9A-Fa-f][0-9A-Fa-f]{0,3}):){0,4}(0|[1-9A-Fa-f][0-9A-Fa-f]{0,3}))?::)((0|[1-9A-Fa-f][0-9A-Fa-f]{0,3}):(0|[1-9A-Fa-f][0-9A-Fa-f]{0,3})|(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9]?[0-9])(\.(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9]?[0-9])){3})|(((0|[1-9A-Fa-f][0-9A-Fa-f]{0,3}):){0,5}(0|[1-9A-Fa-f][0-9A-Fa-f]{0,3}))?::(0|[1-9A-Fa-f][0-9A-Fa-f]{0,3})|(((0|[1-9A-Fa-f][0-9A-Fa-f]{0,3}):){0,6}(0|[1-9A-Fa-f][0-9A-Fa-f]{0,3}))?::)|(?!IPv6:)[0-9A-Za-z-]*[0-9A-Za-z]:[!-Z^-~]+)])/.test(element.value))) {
Solution 3:[3]
Use join by | for regex or:
df['Match'] = df['Text'].str.contains('|'.join(df1['Criteria 1']))
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | AdamRaichu |
| Solution 2 | |
| Solution 3 |
