How to check for a specific count of letters in a row in a String Java [duplicate]

Question

I want to check if my String contains words with a specific length

String s = "ab a abc ac";
if(s.contains(/*any words with 3 or more letters which would be 'abc'*/){
   //doSomething
}

Is there a way to do this in regex or with a simple method? Similar to

s.contains("[a-za-za-z]"); //or
s.contains().lettersInARow(3);

What I want is to find these and throw an Error when something longer than 2 characters is found

Answer 1

or with a simple method

String s = "?ab a abc ac";
long countWordsWithAtLeastThreeCharacters = 
    Arrays.stream( s.split( " " ) )
    .filter( word -> input.codePoints().toArray().length > 3 )
    .count() ;

I added the FACE WITH MEDICAL MASK to demonstrate that this works with all characters. Avoid using char as it is physically incapable of representing most characters.

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Be aware that in some languages what you may perceive as one "letter" is actually a combination of two characters, a letter followed by a "combining diacritical". Example here. Discussion here.