'How to catch an Error in a Switch statement when the user entered number doesn't exist
I'm trying to error proof my program that basically works as a mini calculator. But I have no idea how to write a "Catch" statement that would detect when the user enters a case number that doesn't exist, in my case anything that is negative or > 4
System.out.println("Hello user! Which operation would you like to use?");
System.out.println("1) + \n2) - \n3) * \n4) /");
Scanner operacijai = new Scanner(System.in);
int operacija = operacijai.nextInt();
int n=1;
do {
try {
switch (operacija) {
case 1:
addingMethod();
n=2;
break;
case 2:
subtractingMethod();
n=2;
break;
case 3:
multiplyingMethod();
n=2;
break;
case 4:
dividingMethod();
n=2;
break;
}
}
catch(Exception e) {
System.out.print("Enter a correct number!");
}
} while(n==1);
operacijai.close();
} ```
Solution 1:[1]
Why do you want to throw an Exception unnecessarily? I suggest you just put a default case in your switch with the required error message. Also, move the input part inside the loop, so that it continues to take input.
I also suggest you use nextLine() instead of nextInt(). Check Scanner is skipping nextLine() after using next() or nextFoo()? to learn more about it.
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
System.out.println("Hello user! Which operation would you like to use?");
System.out.println("1) + \n2) - \n3) * \n4) /");
Scanner operacijai = new Scanner(System.in);
int operacija = 0, n = 1;
boolean valid;
do {
do {
valid = true;
try {
operacija = Integer.parseInt(operacijai.nextLine());
} catch (NumberFormatException e) {
System.out.println("Enter an integer only.");
valid = false;
}
} while (!valid);
switch (operacija) {
case 1:
System.out.println("addingMethod()");
n = 2;
break;
case 2:
System.out.println("subtractingMethod()");
n = 2;
break;
case 3:
System.out.println("multiplyingMethod()");
n = 2;
break;
case 4:
System.out.println("dividingMethod()");
n = 2;
break;
default:
System.out.println("Invalid input");
}
} while (n == 1);
}
}
A sample run:
Hello user! Which operation would you like to use?
1) +
2) -
3) *
4) /
5
Invalid input
Another sample run:
Hello user! Which operation would you like to use?
1) +
2) -
3) *
4) /
a
Enter an integer only.
5
Invalid input
2
subtractingMethod()
Solution 2:[2]
You can also handle the use case in default
It is totally upto your use-case how you are handling the exception, you can also create your custom exception and throw from default
something like:
System.out.println("Hello user! Which operation would you like to use?");
System.out.println("1) + \n2) - \n3) * \n4) /");
Scanner operacijai = new Scanner(System.in);
int operacija = operacijai.nextInt();
int n=1;
do {
try {
switch (operacija) {
case 1:
addingMethod();
n=2;
break;
case 2:
subtractingMethod();
n=2;
break;
case 3:
multiplyingMethod();
n=2;
break;
case 4:
dividingMethod();
n=2;
break;
default:
System.out.print("Enter a correct number!")
throw new CustomException();
}
}
catch(CustomException e) {
System.out.print("Enter a correct number!");
}
} while(n==1);
operacijai.close();
}
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | |
| Solution 2 | Sanyam Goel |
