'How to calculate the euclidian distance between a specified coordinate and 2-d xarray data at once
How to calculate the euclidian distance between a specified coordinate and 2-d xarray data at once (without for loop)?
I wrote the following code. But if the data-size become larger, this script appears to be slow. How can I do the same thing without for loop ?
import math
import xarray as xr
import numpy as np
#set the specified lat, lon
specific_lat = 15
specific_lon = 65
#create sample xarry data
lat = [0, 10, 20]
lon = [50, 60, 70, 80]
#sample data
test_data = np.array([[1,2,3,4],[5,6,7,8],[9,10,11,12]])
#to xarray
data_xarray = xr.DataArray(test_data, dims=("lat","lon"), coords={"lat":lat, "lon":lon})
#calculate distance
xarray_distance = data_xarray #copy
xarray_distance.data[:,:] = 0.0 #zero-reset
for lat in data_xarray.lat.data:
for lon in data_xarray.lon.data:
xarray_distance.loc[{"lat":lat,"lon":lon}] = math.sqrt((lat- spec_lat)**2 + (lon - spec_lon)**2)
print(xarray_distance)
#<xarray.DataArray (lat: 3, lon: 4)>
#array([[21, 15, 15, 21],
# [15, 7, 7, 15],
# [15, 7, 7, 15]])
#Coordinates:
# * lat (lat) int64 0 10 20
# * lon (lon) int64 50 60 70 80
Solution 1:[1]
You need to calculate Cosine weighting by: (lon - spec_lon)**2 and that is equal to (cos(lat)*(lon - spec_lon))
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | General Grievance |
