How to avoid running argument function before the main function

Question

I want to create a function that will react according to the success of the argument function and get the argument function's name.

Something like

def foo(argument_function):
    try:
        argument_function
        print(f"{somehow name of the argument_function} executed successfully.")
    except:
        print(f"{somehow name of the argument_function} failed.")

1. argument_function should be executed only under the try statement. Otherwise, it will give an error and stop the script which I am trying to avoid.
2. {somehow name of the argument_function} should return the name of the argument_function.

for successful attempt:

foo(print("Hello world!"))

should return

>>Hello world!
>>print("Hello world!") executed successfully.

for unsuccessful attempt:

foo(prnt("Hello world!"))

should return

>>prnt("Hello world!") failed.

Answer 1

import typing
def foo(argument_function:typing.Callable):
    try:
        argument_function()
        print(f"{argument_function.__name__} executed successfully.")
    except:
        print(f"{argument_function.__name__} failed.")
print(foo.__name__) # returns foo

Or use:

def foo(argument_function:callable):

__name__ returns function name and if you ensure the function is an object then adding () should run the function