How to add spaces in a string [duplicate]

Question

I am using the python module, markovify. I want to make new words instead of making new sentences.

How can I make a function return an output like this?

spacer('Hello, world!') # Should return 'H e l l o ,   w o r l d !'

I tried the following,

def spacer(text):
  for i in text:
    text = text.replace(i, i + ' ')
  return text

but it returned, 'H e l l o , w o r l d ! ' when I gave, 'Hello, world!'

Answer 1

1. You can use this one.

def spacer(string):
    return ' '.join(string)

print(spacer('Hello,World'))

2. Or You can change this into.

def spacer(text):
  out = ''
  for i in text:
    out+=i+' '
  return out[:-1]

print(spacer("Hello, World"))

3. (If you want) You could make the same function into a custom spacer function, But here you also need to pass how many spaces(Default 1) you want in between.

def spacer(string,space=1):
    return (space*' ').join(string)

print(spacer('Hello,World',space=1))

4. OR FOR CUSTOM SPACES.

 
def spacer(text,space=1):
  out = ''
  for i in text:
    out+=i+' '*space
  return out[:-(space>0) or len(out)]

print(spacer("Hello, World",space=1))

.? OUTPUT.

H e l l o ,   W o r l d

Answer 2

The simplest method is probably

' '.join(string)

Since replace works on every instance of a character, you can do

s = set(string)
if ' ' in s:
    string = string.replace(' ', '  ')
    s.remove(' ')
for c in s:
    string = string.replace(c, c + ' ')
if string:
    string = string[:-1]

The issue with your original attempt is that you have ox2 and lx3 in your string. Replacing all 'l' with 'l ' leads to l . Similarly for o .

Answer 3

The simplest answer to this question would be to use this:-

"Hello world".replace("", " ")[1:-1]

This code reads as follows:- Replace every empty substring with a space, and then trim off the trailing spaces.

Answer 4

print(" ".join('Hello, world!'))

Output

H e l l o ,   w o r l d !