how do I output a list of strings that fall alphabetically between two input values

Question

I'm given a text file called input1.txt1 this file contains the following

aspiration
classified
federation
graduation
millennium
philosophy
quadratics
transcript
wilderness
zoologists

Write a program that first reads in the name of an input file, followed by two strings representing the lower and upper bounds of a search range. The file should be read using the file.readlines() method. The input file contains a list of alphabetical, ten-letter strings, each on a separate line. Your program should output all strings from the list that are within that range (inclusive of the bounds).

EX:

Enter the path and name of the input file: input1.txt
Enter the first word: ammunition
Enter the second word (it must come alphabetically after the first word): millennium

The words between ammunition and millennium are:
aspiration
classified
federation
graduation
millennium

Answer 1

file_to_open = input()
bound1 = input()
bound2 = input()

with open(file_to_open) as file_handle:
    list1 = [line.strip() for line in file_handle]

out = [x for x in list1 if x >= bound1 and x <= bound2]

out.sort()
print('\n'.join(map(str, out))) 

Answer 2

Use a list comprehension with inequalities to check the string range:

out = [x for x in your_list if x >= 'ammunition' and x <= 'millennium']

This assumes that your range is inclusive on both ends, that is, you want to include ammunition and millennium on both ends of the range.

To further sort the out list and then write to a file, use:

out.sort()
f = open('output.txt', 'w')
text = '\n'.join(out)
f.write(text)
f.close()

Answer 3

if you should use readline() try this :

filepath = 'Iliad.txt'
start = 'sometxtstart'
end = 'sometxtend'
apending = False
out = ""
with open(filepath) as fp:
    line = fp.readline()
    while line:
        txt = line.strip()
        if(txt == end):
            apending = False
        if(apending):
            out+=txt + '\n'
        if(txt == start):
            apending = True               
        line = fp.readline()
print(out)

Answer 4

This worked for me:

file = input()
first = input()
second = input()


with open(file) as f:
    lines = f.readlines()
    for line in lines:
        l = line.strip('\n')
        if (l >= first) and (l <= second):
            print(line.strip())
        else:
            pass