'How do I get the child folder name of the path besides these methods?
Of the given path like "level1/level2/level3/", I'd like pass it through some operation and get the result like "level3/". So I made two trials like these:
TRIAL 1:
After finding parent property within the Path object, I looked for something close to a child property, but could not.
>>> from pathlib import Path
>>> path = Path("level1/level2/level3/")
>>> path.parent
WindowsPath('level1/level2')
>>> str(path.parent)
'level1\\level2'
TRIAL 2: I used the os module like this:
>>> import os
>>> os.path.basename("level1/level2/level3/".strip("/")) + "/"
'level3/'
Is there an alternative to TRIAL 2, or can I make something work within TRIAL 1 from the pathlib package or Path class?
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|
