'How do I compare two lists in python
I have two lists. The first list contains only strings (basically, it contains foreign words) and the second list contains only strings (it's composed of the words the user already knows). I want to compare the two lists and remove from list 1 the words of list 2. How can I do that?
My attempt:
all_words = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I']
def compare_lists (all_words):
known_words = ['A', 'B', 'C', 'D', 'E',]
for i in all_words:
if i in known_words:
all_words.remove(i)
return all_words
unknown_words = compare_lists(all_words)
print(unknown_words)
Expected output: F, G, H, I.
A long story short, the code doesn't work. I can't quite pinpoint what it does but it seems to remove only one word from the "all_words" list (probably, the code doesn't even work at all but that's just my impression).
Thank you in advance.
Solution 1:[1]
You could use set() https://docs.python.org/3/library/functions.html#func-set:
for example :
s1 = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I'])
s2 = set(['A', 'B', 'C', 'D', 'E', 'F'])
final_words = s1 - s2
print(final_words)
# {'H', 'I', 'G'}
Solution 2:[2]
The problem with your code is that you're deleting the elements in the same array on which you're iterating. You can try this:
all_words = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I']
def compare_lists (all_words):
known_words = ['A', 'B', 'C', 'D', 'E']
temp = all_words[:]
for i in temp:
if i in known_words:
all_words.remove(i)
return all_words
unknown_words = compare_lists(all_words)
Output:
['F', 'G', 'H', 'I']
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Enzo Ramirez C. |
| Solution 2 |
