'how can I write a code to read each name in a file
I typed 3 names in the file, and I wanted to write a code to count how many times each name was repeated (Example: Alex was repeated in the file 3 times..and so on). The code I wrote only counted each name once, and this is wrong because the names were repeated more than once. Can you help me with the part that could be the cause of this problem?
public class MainClass {
public static void readFile() throws IOException {
//File file;
FileWriter writer=null;
String name, line;
List <String> list = new ArrayList <>();
int countM = 0, countAl = 0, countAh = 0;
try
{
File file = new File("\\Users\\Admin\\Desktop\\namesList.txt");
Scanner scan = new Scanner(file);
while(scan.hasNextLine()) {
line = scan.nextLine();
list.add(line);
}
for (int i=0; i<list.size(); i++)
{
name=list.get(i);
if (name.equals("Ali"))
{
countAl= +1;
}
if (name.equals("Ahmed"))
{
countAh= +1;
}
if (name.equals("Muhammad"))
{
countM = +1;
}
}
Collections.sort(list);
writer = new FileWriter("\\Users\\Admin\\Desktop\\newNameList");
for(int i=0; i<list.size(); i++)
{
name = list.get(i);
writer.write(name +"\n");
}
writer.close();
System.out.println("How many times is the name (Ali) in the file? " + countAl);
System.out.println("How many times is the name (Ahmed) in the file? " + countAh);
System.out.println("How many times is the name (Muhammad) in the file? " + countM);
}
catch(IOException e) {
System.out.println(e.toString());
}
}
public static void main(String[] args) throws IOException {
readFile();
}
}
Solution 1:[1]
try:
for (int i=0; i<list.size(); i++)
{
name=list.get(i);
if (name.equals("Ali"))
{
countAl += 1;
}
if (name.equals("Ahmed"))
{
countAh += 1;
}
if (name.equals("Muhammad"))
{
countM += 1;
}
}
This works with me.
+= is not same =+
Solution 2:[2]
You an do this much simpler:
//Open a reader, this is autoclosed so you don't need to worry about closing it
try (BufferedReader reader = new BufferedReader(new FileReader("path to file"))) {
//Create a map to hold the counts
Map<String, Integer> nameCountMap = new HashMap<>();
//read all of the names, this assumes 1 name per line
for (String name = reader.readLine(); name != null; name = reader.readLine()) {
//merge the value into the count map
nameCountMap.merge(name, 1, (o, n) -> o+n);
}
//Print out the map
System.out.println(nameCountMap);
} catch (IOException e) {
e.printStackTrace();
}
Solution 3:[3]
You need to process each line bearing in mind that the file may be very large in some cases. Better safe than sorry. You need to consider a solution that does not take up so much resources.
Streaming Through the File
I'm going to use a java.util.Scanner to run through the contents of the file and retrieve lines serially, one by one:
FileInputStream inputStream = null;
Scanner sc = null;
try {
inputStream = new FileInputStream(file_path);
sc = new Scanner(inputStream, "UTF-8");
while (sc.hasNextLine()) {
String line = sc.nextLine();
// System.out.println(line);
}
// note that Scanner suppresses exceptions
if (sc.ioException() != null) {
throw sc.ioException();
}
} finally {
if (inputStream != null) {
inputStream.close();
}
if (sc != null) {
sc.close();
}
}
This solution will iterate through all the lines in the file – allowing for processing of each line – without keeping references to them – and in conclusion, without keeping them in memory:
Streaming With Apache Commons IO
The same can be achieved using the Commons IO library as well, by using the custom LineIterator provided by the library:
LineIterator it = FileUtils.lineIterator(your_file, "UTF-8");
try {
while (it.hasNext()) {
String line = it.nextLine();
// do something with line
}
} finally {
LineIterator.closeQuietly(it);
}
Since the entire file is not fully in memory – this will also result in pretty conservative memory consumption numbers.
BufferedReader
try (BufferedReader br = Files.newBufferedReader(Paths.get("file_name"), StandardCharsets.UTF_8)) {
for (String line = null; (line = br.readLine()) != null;) {
// Do something with the line
}
}
ByteBuffer
try (SeekableByteChannel ch = Files.newByteChannel(Paths.get("test.txt"))) {
ByteBuffer bb = ByteBuffer.allocateDirect(1000);
for(;;) {
StringBuilder line = new StringBuilder();
int n = ch.read(bb);
// Do something with the line
}
}
The above examples will process lines in a large file without iteratively, without exhausting the available memory – which proves quite useful when working with these large files.
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | salim alzuhairi |
| Solution 2 | Ryan |
| Solution 3 | David Kariuki |
