How can I split Flask app.py's decorated functions into another file?

Question

I want to keep my Flask app.py small by pushing the decorated functions into another file.

I couldn't find a Pythonic way of doing it, but is there a Flask way?

This currently works:

import os

from config import Config
from context_processors.url_processors import prefixed_url_for
from flask import Flask
from greetings.views import greetings
from services.relational_database import db_session, init_db


app = Flask(__name__)
app.config.from_object(Config())

app.register_blueprint(greetings, url_prefix='/greetings/')

init_db()

### can these decorated functions be moved to another file? ###
@app.context_processor
def processors():
    return dict(
        prefixed_url_for=prefixed_url_for,
    )

@app.teardown_appcontext
def shutdown_session(exception=None):
    db_session.remove()
###:end can these decorated functions be moved to another file? ###

if __name__ == "__main__":
    app.run(
        host='0.0.0.0',
        port=os.environ['WEB_PORT'],
        debug=(os.environ['FLASK_ENV'] == 'development'),
        ssl_context=context,
    )

Is there a way to do something like this instead?:

...
from .anotherfile import processors
@app.context_processor
processors

# or even just:
from .anotherfile import decorated_functions
# replacing @app.teardown_appcontext altogether
...

There were ways of importing a decorator from another file, but the decorator is already provided by Flask so that's not what I want in this case.

This post (Flask context processors functions) shows an example of using context_processor, but I've already got that part working. Rather, I want to refactor it to a separate file. So, these 2 lines:

@thingy.context_processor
def utility_processor():

would be in separate files or in a different file than app.py or views.py.

Thank you for your help 🙏