How can I download the exact uploaded file in Django?

Question

I was writing a code to download my file using a link which I have uploaded through the model in Django.

i.e in my model.py

class uploadFile(models.Model):
    id=models.CharField("Book id ",max_length=200,null=True,default="")
    name=models.CharField("Book name",max_length=200,null=True,default="")
    file=models.FileField(upload_to="media/ebooks")

and in my view.py I have 2 functions

def getdata(request):
    books=uploadFile.objects.all()
    n=len(QPapers)
    print("hello",QPapers)
    params={'QPapr':QPapers,'total_items':n}
    return render(request,'index.html',params)

def getdata2(request,nameparam):
    books=uploadFile.objects.all().filter(name=nameparam)
    n=len(QPapers)
    print("hello",QPapers)
    params={'QPapr':QPapers,'total_items':n}
    return render(request,'index.html',params)

and in index.html

 <a href="{% 'getdata' %}" download>download1</a>

for this urls.py is path('getdata',views.pdfNotes,name='pdfNotes'),

here the file downloads correctly using above code but when i am using the below code and calls to 2nd function with the name of book then instead of downloading file i have uploaded it downloads the index.html page.

<a href="{% 'getdata2' 'book1' %}" download>download2</a>

for this urls.py is path('getdata2/<str:name>/',views.pdfNotes,name='pdfNotes'),

Is it because of filter I am using, or is the problem somewhere else? I want to be download the specific file also that's why I am using the filter here...

Answer 1

The name of the parameter of your view is nameparam, not name, you thus specify this in the URL patterns with:

#                      ↓ not name
path('getdata2/<str:nameparam>/',views.pdfNotes,name='pdfNotes'),