'How can I animate a matplotlib plot from within for loop
I would like to update my matplotlibplot with values calculated in each iteration of a for loop. The idea is that I can see in real time which values are calculated and watch the progress iteration by iteration as my script is running. I do not want to first iterate through the loop, store the values and then perform the plot.
Some sample code is here:
from itertools import count
import random
from matplotlib.animation import FuncAnimation
import matplotlib.pyplot as plt
def animate(i, x_vals, y_vals):
plt.cla()
plt.plot(x_vals, y_vals)
if __name__ == "__main__":
x_vals = []
y_vals = []
fig = plt.figure()
index = count()
for i in range(10):
print(i)
x_vals.append(next(index))
y_vals.append(random.randint(0, 10))
ani = FuncAnimation(fig, animate, fargs=(x_vals, y_vals))
plt.show()
Most of the examples I have seen online, deal with the case where everything for the animation is global variables, which I would like to avoid. When I use a debugger to step through my code line by line, the figure does appear and it is animated. When I just run the script without the debugger, the figure displays but nothing is plot and I can see that my loop doesn't progress past the first iteration, first waiting for the figure window to be closed and then continuing.
Solution 1:[1]
trying to elaborate on @dumbpotato21 answer, here my attempt:
import random
from matplotlib.animation import FuncAnimation
import matplotlib.pyplot as plt
def data():
cnt = 0
x = []
y = []
for i in range(1,10):
# x = []
# y = []
x.append(cnt*i)
y.append(random.randint(0, 10))
cnt += 1
yield x, y, cnt
input('any key to exit !!!')
quit()
def init_animate():
pass
def animate( data, *fargs) :
print('data : ', data, '\n data type : ', type(data), ' cnt : ', data[2])
plt.cla()
x = [i*k for i in data[0]]
y = [i*p for i in data[1]]
plt.plot(x,y)
if __name__ == "__main__":
fig = plt.figure()
k = 3
p = 5
ani = FuncAnimation(fig, animate, init_func=init_animate, frames=data, interval=700, fargs = [k,p])
plt.show()
Solution 2:[2]
There are a number of alternatives which might come in handy in different situations. Here is one that I have used:
import matplotlib.pyplot as plt
import numpy as np
from time import sleep
x = np.linspace(0, 30, 51)
y = np.linspace(0, 30, 51)
xx, yy = np.meshgrid(x, y)
# plt.style.use("ggplot")
plt.ion()
fig, ax = plt.subplots()
fig.canvas.draw()
for n in range(50):
# compute data for new plot
zz = np.random.randint(low=-10, high=10, size=np.shape(xx))
# erase previous plot
ax.clear()
# create plot
im = ax.imshow(zz, vmin=-10, vmax=10, cmap='RdBu', origin='lower')
# Re-render the figure and give the GUI event loop the chance to update itself
# Instead of the two lines one can use "plt.pause(0.001)" which, however gives a
# decepracted warning.
# See https://github.com/matplotlib/matplotlib/issues/7759/ for an explanation.
fig.canvas.flush_events()
sleep(0.1)
# make sure that the last plot is kept
plt.ioff()
plt.show()
Additionally, the set_data(...) method of a line plot or imshow object is useful if only the data changes and you don't want to re-drw the whole figure (as this is very time consuming).
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | pippo1980 |
| Solution 2 |
