'How can a shell function know if it is running within a virtualenv?
How should a bash function test whether it is running inside a Python virtualenv?
The two approaches that come to mind are:
[[ "$(type -t deactivate)" != function ]]; INVENV=$?
or
[[ "x$(which python)" != "x$VIRTUAL_ENV/bin/python" ]]; INVENV=$?
(Note: wanting $INVENV to be 1 if we're inside a virtualenv, and 0 otherwise, is what forces the backward-looking tests above.)
Is there something less hacky?
Solution 1:[1]
if [[ "$VIRTUAL_ENV" != "" ]]
then
INVENV=1
else
INVENV=0
fi
// or shorter if you like:
[[ "$VIRTUAL_ENV" == "" ]]; INVENV=$?
EDIT: as @ThiefMaster mentions in the comments, in certain conditions (for instance, when starting a new shell – perhaps in tmux or screen – from within an active virtualenv) this check may fail (however, starting new shells from within a virtualenv may cause other issues as well, I wouldn't recommend it).
Solution 2:[2]
If you use virtualenvwrappers there are pre/post scripts that run that could set INVENV for you.
Or what I do, put the following in your your .bashrc, and make a file called .venv in your working directory (for django) so that the virtual env is automatically loaded when you cd into the directory
export PREVPWD=`pwd`
export PREVENV_PATH=
handle_virtualenv(){
if [ "$PWD" != "$PREVPWD" ]; then
PREVPWD="$PWD";
if [ -n "$PREVENV_PATH" ]; then
if [ "`echo "$PWD" | grep -c $PREVENV_PATH`" = "0" ]; then
deactivate
unalias python 2> /dev/null
PREVENV_PATH=
fi
fi
# activate virtualenv dynamically
if [ -e "$PWD/.venv" ] && [ "$PWD" != "$PREVENV_PATH" ]; then
PREVENV_PATH="$PWD"
workon `basename $PWD`
if [ -e "manage.py" ]; then
alias python='python manage.py shell_plus'
fi
fi
fi
}
export PROMPT_COMMAND=handle_virtualenv
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | |
| Solution 2 | Kurt |
