HackerRank Staircase Python

Question

I am trying to solve a problem in HackerRank and I am having an issue with my submission. My code works in PyCharm but HackerRank is not accepting my submission.

Here is the problem I am trying to solve: https://www.hackerrank.com/challenges/staircase

Here is my code:

def staircase(num_stairs):
    n = num_stairs - 1
    for stairs in range(num_stairs):
        print ' ' * n, '#' * stairs
        n -= 1
    print '#' * num_stairs
staircase(12)

Any ideas why HackerRank is not accpeting my answer?

Answer 1

You can use rjust to justify the string to the right:

def staircase(n):
    for i in range(1, n+1):
         print(("#" * i).rjust(n))

Answer 2

Another solution

n = int(raw_input())
s = '#'
for i in xrange( 1 , n+1):
    print " "*(n-i) + s*i

Answer 3

first, create a list, then print with join \n'

def staircase(n):
    print("\n".join([' ' * (n-x) + '#' * x for x in range(1, n+1)]))

Answer 4

def staircase(n):
    for i in range(0, n): # n rows 
        print(' '*(n-i-1) + '#'*(i+1)) # first print n-i-1 spaces followed by i '#'


n = int(input())
staircase(n)

Answer 5

its look like secondary diagonal

 def staircase(n):
        for i in range(n):
            for j in range (n):
                if i+j == n-1:
                    print(" "*j+"#"*(n-j))

output-

     #
    ##
   ###
  ####
 #####
######

Answer 6

for i in range(n):
    result = ' '*(n-i-1) +('#')*(i+1)
    print(result)

Answer 7

I was getting an error until I replaced the comma with a plus sign:

print(' ' * (n - i - 1) + '#' * (i + 1))

Answer 8

Understanding the problem is 80% of the solution. The requirement states the min/max total of stairs.

"""
Prints a staircase with a total number of stairs
Note: total number of stairs must be between 1 and 100 inclusive, as per requirements
"""
def staircase(n):
    if n < 1 or n > 100:
        print("Error: Total number of stairs must be between 1, 100 inclusive!")
    else:
        for x in range(1, n+1):
            print(" " * (n - x) + "#" * x )

#-----------------------
staircase(0)
Error: Total number of stairs must be between 1, 100 inclusive!

staircase(101)
Error: Total number of stairs must be between 1, 100 inclusive!

staircase(4)
   #
  ##
 ###
####

Answer 9

def staircase(n):
    space = n-1
    for i in range(n):
        x = i + 1
        print(" " * space + "#" * x)
        space -= 1

Answer 10

one more solution:

def staircase(n):
    for i in reversed(range(n)):
        print(i*' '+(n-i)*'#')

Answer 11

You can just change the sep argument of print from ' ' to '', and your answer will be correct

def staircase(n):    
    for i in range(1, n+1):
        print(' ' * (n-i), '#' * (i), sep='')

The answer you submitted is not accepted because the default print settings adds an empty space in front of the printouts, and one of the question requirements is for there to have no spaces in the output.

The default sep in print is a space character i.e. ' '.

Answer 12

Another Answer

    H = int(input())
    for i in range(1,H+1):
       H = H - 1
       print(' '*(H) + ('#'*(i)))

Answer 13

you can simply use while loop also.

import sys
n1=int(raw_input())-1
n2=1

while n1>=0:
    print " "*n1,"#"*n2
    n1=n1-1
    n2=n2+1

Answer 14

Here's a solution I came up with that uses a while loop and counter.

def staircase(n):
    counter = 1
    while n:
        print((abs(1-n)*' ') + ('#'*counter))
        n -= 1
        counter += 1 

Answer 15

 def staircase(n):
     for in range(i,n+1):
          print str("#"*i).rjust(n)