Get the year from specified date php

Question

I have a date in this format 2068-06-15. I want to get the year from the date, using php functions. Could someone please suggest how this could be done.

Answer 1

$date = DateTime::createFromFormat("Y-m-d", "2068-06-15");
echo $date->format("Y");

The DateTime class does not use an unix timestamp internally, so it han handle dates before 1970 or after 2038.

Answer 2

You can use the strtotime and date functions like this:

echo date('Y', strtotime('2068-06-15'));

Note however that PHP can handle year upto 2038

You can test it out here

---

If your date is always in that format, you can also get the year like this:

$parts = explode('-', '2068-06-15');
echo $parts[0];

Answer 3

I would use this:

$parts = explode('-', '2068-06-15');
echo $parts[0];

It appears the date is coming from a source where it is always the same, much quicker this way using explode.

Answer 4

You can try strtotime() and date() functions for output in minimum code and using standard way.

echo date('Y', strtotime('2068-06-15'));

output: 2068

echo date('y', strtotime('2068-06-15'));

output: 68

Answer 5

  public function getYear($pdate) {
    $date = DateTime::createFromFormat("Y-m-d", $pdate);
    return $date->format("Y");
}

public function getMonth($pdate) {
    $date = DateTime::createFromFormat("Y-m-d", $pdate);
    return $date->format("m");
}

public function getDay($pdate) {
    $date = DateTime::createFromFormat("Y-m-d", $pdate);
    return $date->format("d");
}

Answer 6

<?php
list($year) = explode("-", "2068-06-15");
echo $year;
?>

Answer 7

You can achieve your goal by using php date() & explode() functions:

$date = date("2068-06-15");

$date_arr = explode("-", $date);

$yr = $date_arr[0];

echo $yr;

That is it. Happy coding :)

Answer 8

Assuming you have the date as a string (sorry it was unclear from your question if that is the case) could split the string on the - characters like so:

$date = "2068-06-15";
$split_date = split("-", $date);
$year = $split_date[0];

Answer 9

$Y_date = split("-","2068-06-15");
$year = $Y_date[0];

You can use explode also

Answer 10

You wrote that format can change from YYYY-mm-dd to dd-mm-YYYY you can try to find year there

$parts = explode("-","2068-06-15");
for ($i = 0; $i < count($parts); $i++)
{
     if(strlen($parts[$i]) == 4)
     {
          $year = $parts[$i];
          break;
      }
  }